A regular quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.
Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges with measure 16 cm is 4.
Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.
Multiply .30 and 50 ... which is 15
Answer:
47%
Step-by-step explanation:
9.2/19.5=0.47179
the number in the tenth place is 7 and It can´t be changed because 1 isn´t 5 or it also isn´t greater than 5.
64; Line pq is correspondent with line ab and triangle PQR is 4 time as big as triangle ABC.
Well 8x25x23 = 4,600 but what do you need to subtract by?
