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3 years ago

PLEASE HELP!!!!!Find the equation of each line and then put each equation into the form Ax+By=C where A,B, and C are integers

Mathematics

1 answer:

shutvik [7]3 years ago

4 0

Answer:

y-5x-7=0

Step-by-step explanation:

m = -2-3/1-2

m=5

y-y1 = m(x-x1)

y-2=5(x+3)

y-2=5x +5

y-5x-7=0

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If y=3.2 when x=1.6,find y when x=19

In-s [12.5K]

Y = 38

3.2 / 1.6 = 2
x / 19 = 2
2 x 19 = 38

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4 years ago

Read 2 more answers

What is the constant of variation for the quadratic variation?

Lorico [155]

Given:
x = 2 3 4 5 6
y = 20 ; 45 ; 80; 125;180

The constant variation for the quadratic variation is 5.

y = 5x²
y = 5(2²) = 5(4) = 20
y = 5(3²) = 5(9) = 45
y = 5(4²) = 5(16) = 80
y = 5(5²) = 5(25) = 125
y = 5(6²) = 5(36) = 180

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4 years ago

5. a.5 b.4<br> C. 40<br> d. 130

mario62 [17]

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8 0

3 years ago

Use f(x) = 1)2 and f^-1(x) = 2x to solve the problems. a) f(2) b)f^-1(1) c)f^-1(f(2))

Luden [163]

a) f (2) = 1

b) $f^{-1}(1)=2$

c) $f^{-1}(f(2))=2$

<u>Step-by-step explanation:</u>

$f^{-1}$ - Indicates that we have to find the inverse of the function

Given data:

$f(x)=\left(\frac{1}{2}\right) x$ --------> eq.1

$f^{-1}(x)=2 x$ ---------> eq.2

To find $f(2), f^{-1}(1), f^{-1}(f(2))$

Case a)

Now, substitute x = 2 in the equation 1 to find f (2)

$f(2)=\left(\frac{1}{2}\right) \times 2=1$

Case b)

Now, substitute x = 1 in the equation 2 to find $f^{-1}(1)$

$f^{-1}(1)=2(1)=2$

Case c)

In general,

$f^{-1}(f(x))=f\left(f^{-1}(x)\right)=x$

Thereby,

$f^{-1}(f(2))=2 \text { where } x=2$

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3 years ago

42=-2d+6 I need help.

mixer [17]

Ans given below
42-6=-2d

36=-2d
d=-18

7 0

3 years ago