Answer:
Between 19 and 55, inclusive
Step-by-step explanation:
70 < Average < 79 (inclusive)
4×70 < sum < 4×79 (inclusive)
280 < sum < 316
280 < 92 + 84 + 85 + X < 316
280 < 261 + X < 316
19 < x < 55
Fourth score can be between 19 and 55, inclusive
Knowing that a quadratic equation has two possible solutions, we need to be careful when we solve exponential equations in checking for any quadratic one that appears. Due to 2 possible solutions,
Hope I helped :)
4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2
This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4
To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)
If you multiply this as well you get the same answer I got with the addition
Answer:
the anser
Step-by-step explanation:
this is faze jarvis hahah
the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
