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krek1111 [17]
3 years ago
15

What is the equation of a line with a y-intercept of 2 and an x-intercept of 4?

Mathematics
1 answer:
Ronch [10]3 years ago
5 0
The equation is y=(-1/2)x +2
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Lisa collected leaves from different trees for a science project. Every day for a week (7 days), she collected 7 leaves. How man
blagie [28]
7 leaves per day for a whole week
there are seven days in a week
7 times 7 is 49
because she picked up seven leaves per day for a week straight

8 0
4 years ago
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Akira Chang's uncle dies without a will, leaving an estate of $945,000. His heirs consist of a wife and two adult children. His
OLEGan [10]
Let w represent the amount the wife receives.
.. w +2*(2/3*w) = 945,000
.. 7/3w = 945,000
.. w = (3/7)*945,000 = 405,000

The wife will receive $405,000.
5 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
Use the diagram and the following equation to solve for x.
Lemur [1.5K]

Starting with 113+ (2x+5)=180, combine like terms and to get 118+2x=180.  Subtract 180-118, which gives you 62.  Then you have 2x=62.  Divide both sides by 2 to get a final answer of x=31.

8 0
3 years ago
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PLEASE!!! ASAP!!! WILL GIVE BRANLIEST!!! SHOW & EXPLAIN!!
pashok25 [27]

Answer:

365 messages

Step-by-step explanation:

x = # text messages)

16.5 = 10 + .10(x - 300)

6.5 = .10x - 30

36.5 = .10x

x = 365

6 0
3 years ago
Read 2 more answers
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