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kkurt [141]
3 years ago
8

Which of these expressions is equivalent to log (15/7)

Mathematics
2 answers:
ki77a [65]3 years ago
5 0

Answer:

log(15)-log(7)

Step-by-step explanation:

LiRa [457]3 years ago
4 0

Answer:

log(15)-log(7)

Step-by-step explanation:

just trust me cuh

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Marci bought 4 yards of ribbon for $6 how much should marci expect to pay for 10 yards of the ribbon?
Vinvika [58]
Ok, let's find how much does 1 yard of ribbon cost. Let's divide!

6 / 4 = 1.5

Each yard costs $1.50, so let's multiply that by 101.5 * 10 = 15

Marci will pay $15 for 10 yards of the ribbon.
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42/6 = 7 laps per race
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Graph -7x+5y=35<br> Please i need help
Lelu [443]

Answer:

Look at the attached image for the answer.

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mike, dave and john worked for a total of 56 hours. Dave worked 6 more than 4 times as many hours as mike. John worked 6 less th
Daniel [21]

Answer:

1. Dave worked for 34 hours.

2. Perimeter of the rectangle is 172 cm.

Step-by-step explanation:

1. Determination of the hours Dave worked.

Let D represent Dave.

Let M represent Mike.

Let J represent John.

Tota time worked by Dave, Mike and John is 56 hours. This can be written as:

D + M + J = 56 ..... (1)

Dave worked 6 more than 4 times as many hours as Mike. This can written as:

D = 6 + 4M .....(2)

John worked 6 less than 3 times as many hours as Mike. This can be written as:

J = 3M – 6 ........ (3)

Substituting the value of F and J into equation 1, we have:

D + M + J = 56

D = 6 + 4M

J = 3M – 6

6 + 4M + M + 3M – 6 = 56

6 – 6 + 4M + M + 3M = 56

8M = 56

Divide both side by 8

M = 56/8

M = 7

Substitute the value of M into equation (2) to obtain the value of D.

D = 6 + 4M

M = 7

D = 6 + 4(7)

D = 6 + 28

D = 34

Therefore, Dave worked for 34 hours .

2. Determination of the perimeter.

Length (L) = 64 cm

Width (W) = 22 cm

Perimeter (P) =?

P = 2(L + W)

P = 2 (64 + 22)

P = 2 (86)

P = 172 cm

Therefore, the perimeter of the rectangle is 172 cm

6 0
3 years ago
A government bureau publishes annual price figures for new mobile homes. A simple random sample of 36 new mobile homes yielded t
Oliga [24]

Answer:

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The prices in thousands of dollar are:</em>

<em>66.6, 69.8, 58.4, 57.3, 63.1, 61.8, 56, 72.7, 61.8,  </em>

<em>66.9, 72.6, 63.1, 58.7, 65.9, 61.1, 56.1, 49.9, 72.6,  </em>

<em>49, 56.4, 72.6, 60.1, 65, 64.8, 56.5, 52, 53.2,  </em>

<em>56.4, 75.4, 76.3, 60.5, 74.6, 57, 69.2, 62.7, 77.2.</em>

<em />

We have a sample of n=36 new mobile homes.

The mean of this sample is:

M=(1/36)\sum_{i=1}^{36}x_i=\dfrac{2273.3}{36}=63.147

The population standard deviation is σ=7.5 (in thousands of dollars).

The critical value of z for a 99.7% CI is z=2.97.

Then, we can calculate the margin of error as:

E=z\cdot \sigma/\sqrt{n}=2.97*7.5/\sqrt{36}=22.275/9=2.475

Now we can calculate the lower and upper bound of the confidence interval as:

LL=\bar X-E=63.147-2.475=60.672\\\\UL=\bar X+E=63.147+2.475=65.622

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

8 0
3 years ago
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