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jarptica [38.1K]
3 years ago
11

Please solve this sheet.

Mathematics
1 answer:
lyudmila [28]3 years ago
6 0
Hello,

A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)

y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1

eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1

Answer :A--> R,K

B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10

answer B--> I,≈W if it is written -1/2*x²  (square has been forgotten)

C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J

D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L

E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!

y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.

y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]




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Given: m∠EYL=72°<br> Find: mEHL , mLVE
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Answer:

Part 1) The measure of arc EHL is 108\°

Part 2) The measure of angle LVE is 54\°

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

so

m

we have

m

substitute

72\°=\frac{1}{2}(y-x)

144\°=(y-x)

y=144\°+x ------> equation A

Remember that

x+y=360\° -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

x+(144\°+x)=360\°

2x=360\°-144\°

x=216\°/2=108\°

Find the value of y

y=144\°+x

y=144\°+108\°=252\°

therefore

The measure of arc EHL is 108\°

The measure of arc EVL is 252\°

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

m

we have

x=108\°

substitute

m

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