Select all of the solutions to the equation below. 12x2=24

kirza4 [7]

Answer:

(1,0)

Step-by-step explanation:

This is because a system of equations is when two lines cross to form a point that they share. (1,0) is the point where the two lines cross/intersect.

6 0

2 years ago

Read 2 more answers

Day 4: As a landscaper, one of your clients wants a rectangular garden in which the length is five feet

liberstina [14]

Answer:

The Area of Rectangular Garden is 1044 feet²

Step-by-step explanation:

According to question

The perimeter of the garden = 82 ft

Let the length be L ft

The width be W ft

Now as per question

L = 5 + ( 2× W )

∵ Perimeter of Rectangle = 2 × ( Length + Width )

Or , Perimeter of Rectangle = 2 × ( L+ W )

Or, 82 = 2 × ( L+ W )

Or, 82 = 2 × [ 5 + ( 2 ×W ) + W ) ]

Or, 82 = 2 × ( 5 +3W )

Or, 41 = 5 + 3W

Or, 41 - 5 = 3W

So, 3W= 36

∴ W = $\frac{36}{3}$ = 12 feet

I.e Width = 12 feet

And L = 5 + ( 2× W )

Or, Length = 5 + 24 = 29 feet

Now The Area of Rectangle = Length × width

So, The Area of Rectangle = 29 ft × 36 ft

The Area of Rectangle is 1044 feet²

Hence The Area of Rectangular Garden is 1044 feet² Answer

4 0

3 years ago

Find the sale price to the nearest cent .. $40 sweater; 33%discount

fiasKO [112]

Answer:

$26.80

Step-by-step explanation:

(I don't know exactly how other people were taught to do percentages, but this is how I was taught and I find it the easiest for me.)

You are going to subtract your percentage number by 100.

100 - 33 = 67

This will give you your multiplier so you can then get your answer but you have to turn it into a decimal.

0.67 x 40 = 26.80

8 0

3 years ago

Which expressions are equivalent to 4x^4-9x^2?

weeeeeb [17]

We can cosider this to be a difference of 2 squares so

4x^4 - 9x^2 = (2x^2 - 3x)(2x^2 + 3x) so D is one answer

also we could take x^2 out and get
x^2(4x^2 - 9) = C

3 0

3 years ago

Both the La Plata river dolphin (Pontoporia blainvillei) and

Citrus2011 [14]

Answer:

1. A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin; 2. The radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball; 3. The volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

or

$\\ 1 \leq a < 10$ (3)

Then, b represents the order of magnitude of such a number (Order of magnitude (2020), in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The La Plata river dolphin weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the scientific notation):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin.

<h3>Second case</h3>

Following the same reasoning, we can conclude that the radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball:

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$