Answer:
See below.
Step-by-step explanation:
This is focusing on the order of operations.
PEMDAS = Parenthesis, exponents, multiplication, division, addition, subtraction.
40 ÷ [(18 - 9) - (13 - 12)]
40 ÷ [9 - 1]
40 ÷ 8
5
[(13 - 9) · 3] + [(14 - 8) · 2]
[4 · 3] + [6 · 2]
12 + 12
24
Hi there!
To find the average speed of a moving object all you need to do is divide the distance traveled by the object by amount of time it took the object to reach its final destination. So for this problem it would go like this:
325 ÷ 5 = 65
So for this problem in particular the answer is 65 MPH was the average speed of the train.
Your friend, ASIAX
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I =
Area of ΔADC =
=
=
=
=
= 30 cm²
Area of equilateral triangle II =
Area of equilateral triangle II =
=
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH =
Since, GH = GJ + JK + KH
17 =
12 =
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² +
-81 = -x² +
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV =
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
Answer:
8 x 10¹³ is your answers hopes it's helpful to you
The The likeness of an event happening