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3 years ago

ASPA.... PLS HELP

Mathematics

2 answers:

saveliy_v [14]3 years ago

5 0

The answer would be y=-2x-5 since we want to get y by itself, we need to subtract 2x on both sides

vlabodo [156]3 years ago

4 0

Answer:

y = -2x - 5

Step-by-step explanation:

to get the equation into slope-intercept form, you need to get y by itself and to to that you subtract 2x from the left side and -5 stas negative 5 cuz you didnt do anything to it so it would be y = -2x -5

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Answer:

X=6

Step-by-step explanation:

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3 years ago

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3 years ago

What is the value of the expression below? 32^3/5 O A. 6/5 B. 6 O c. 96/5 O D. 8

Hoochie [10]

Answer:

D. 8

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2 years ago

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Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

The lines below are parallel. If the slope of the green line is -4, what is the slope of the red line?

kodGreya [7K]

Answer:

-4

Step-by-step explanation:

Hey there!

Well the slopes of 2 parallel lines have the same slope,

meaning if the green line has a slope of -4 then the slope of the red line has a slope of -4.

Hope this helps :)

5 0

3 years ago