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3 years ago

ASPA.... PLS HELP

Mathematics

2 answers:

saveliy_v [14]3 years ago

5 0

The answer would be y=-2x-5 since we want to get y by itself, we need to subtract 2x on both sides

vlabodo [156]3 years ago

4 0

Answer:

y = -2x - 5

Step-by-step explanation:

to get the equation into slope-intercept form, you need to get y by itself and to to that you subtract 2x from the left side and -5 stas negative 5 cuz you didnt do anything to it so it would be y = -2x -5

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In the figure to the right, AB = 7 1/2 m, BC = 2 1/4 m, and DE = 1 1/4 m. Find the perimeter of the figure if all angles are rig

Andreas93 [3]

Answer:

Perimeter=22 m

Step-by-step explanation:

Perimeter Of A Figure

Perimeter is the distance measured around a shape. If the figure is line-shaped, the perimeter can be obtained by adding the individual lengths of each segment around the shape.

The figure shown is surrounded by line segments. We only have to add them all to find the perimeter. But we don't need each individual length to do so. We may notice the following (given all angles are right):

The sum of HG+FE+DC equals AB. So the upper and lower lengths are twice AB, or equivalently: 2*7 1/2 m =15 m

It can also be noted that AH+GF=BC+DE=2 1/4+1 1/4 = 3 1/2 m. It means that the two lateral lengths are twice this value: 2* 3 1/2 = 7 m

Thus, the total perimeter is 15 m + 7 m = 22 m

4 0

3 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

Step-by-step explanation:

The random variable X is defined as the number of seconds for a randomly selected lap.

The random variable X is normally distributed with mean, μ = 129.71 seconds and standard deviation, σ = 2.28 seconds.

Thus, $X\sim N(129.71,\ 2.28^{2})$ .

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

$P(X$

$=P(Z$

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let x represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of z for the above probability is:

z = -1.88

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42$

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let x₁ and x₂ be the values between which the middle 80% of the distribution lie.

That is,

$P(x_{1}$

The value of z for the above probability is:

z = 1.28

Compute the values of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80$ $z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63$