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bekas [8.4K]
3 years ago
11

What connections do you see between variables and what you learned about the Input-Output-Store-Process model of a computer?

Computers and Technology
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

h

Explanation:

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When installing the latest version of Internet Explorer, a dialogue box pops up with a box checked telling you that Bing will be
meriva

Answer:

B) opt-out identify

Explanation:

To opt-out means refusing to or avoiding to accept unsolicited refers to  products or service information. In this caseyou are refusing to accept Bing as your default search provider

8 0
3 years ago
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
In a non-price rationing system, consumers receive goods and services first-come, first served. Give me an example of a time whe
Anna35 [415]

When someone may be giving away something for free.

7 0
2 years ago
Write code which takes a user input of a String and an integer. The code should print each letter of the String the number of ti
Alexus [3.1K]

import java.util.Scanner;

public class JavaApplication70 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Input a String:");

       String txt = scan.nextLine();

       System.out.println("Input an integer:");

       int num = scan.nextInt();

       String newTxt = "";

       int w = 0;

       for (int i = txt.length()-1; i >= 0; i--){

           char c = txt.charAt(i);

           while (w < num){

               newTxt += c;

               w++;

           }

           w = 0;

       }

       System.out.println(newTxt);

   }

   

}

I hope this helps!

7 0
3 years ago
Read 2 more answers
If a computer reboots itself on its own the computer might have a(n)
MissTica

Answer:

D. Software Problem

Explanation:

It could be that the software is bootlooping which will power on and off until its fixed.

4 0
3 years ago
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