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3 years ago

15

Which process centers the spreadsheet's content on the page?

Computers and Technology

1 answer:

riadik2000 [5.3K]3 years ago

6 0

The answer is C: Select the horizontally boxes and vertically boxes in the margins tab of the page setup menu

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A team member who feels uncomfortable when disagreeing with another team member is likely from a(n) _______(fill in the blank) c

Delvig [45]

collectivistic culture

7 0

3 years ago

Write out code for a nested if statement that allows a user to enter in a product name, store the product into a variable called

OlgaM077 [116]

Answer:

product_name = input("Enter product name : ")

if product_name=="pen"or"book"or"box"or"pencil"or"eraser":

if product_name == "pen":

amount = 10

print(f"Product Name: {product_name}\nCost: {amount} rupees")

if product_name == "book":

amount = 100

print(f"Product Name: {product_name}\nCost: {amount} rupees")

if product_name == "box":

amount = 150

print(f"Product Name: {product_name}\nCost: {amount} rupees")

if product_name == "pencil":

amount = 5

print(f"Product Name: {product_name}\nCost: {amount} rupees")

if product_name == "eraser":

amount = 8

print(f"Product Name: {product_name}\nCost: {amount} rupees")

else:

print("Item not found!")

Explanation:

The python program is a code of nested if-statements that compares the input string to five items of the first if-statement. For every item found, its code block is executed.

6 0

3 years ago

Design and implement an algorithm that gets as input a list of k integer values N1, N2,..., Nk as well as a special value SUM. Y

satela [25.4K]

Answer:

Follows are the code to this question:

def FindPair(Values,SUM):#defining a method FindPair

found=False;#defining a boolean variable found

for i in Values:#defining loop for check Value

for j in Values:#defining loop for check Value

if (i+j ==SUM):#defining if block that check i+j=sum

found=True;#assign value True in boolean variable

x=i;#defining a variable x that holds i value

y=j;#defining a variable x that holds j value

break;#use break keyword

if(found==True):#defining if block that checks found equal to True

print("(",x,",",y,")");#print value

else:#defining else block

print("Sorry there is no such pair of values.");#print message

Values=[3,8,13,2,17,18,10];#defining a list and assign Values

SUM=20;#defining SUM variable

FindPair(Values,SUM);#calling a method FindPair

Output:

please find the attachment:

Explanation:

In the above python code a method, "FindPair" is defined, which accepts a "list and SUM" variable in its parameter, inside the method "found" a boolean variable is defined, that holds a value "false".

Inside the method, two for loop is defined, that holds list element value, and in if block, it checks its added value is equal to the SUM. If the condition is true, it changes the boolean variable value and defines the "x,y" variable, that holds its value.
In the next if the block, it checks the boolean variable value, if the condition is true, it will print the "x,y" value, otherwise, it will print a message.

6 0

3 years ago

(BRAINLIEST FOR FIRST CORRECT ANSWER) Mark (all) the statements that best describe the use of spreadsheets and tables in present

mel-nik [20]

the answer is Headers should be descriptive of the cell content, The font size should be at least 18-point. hope this helps!!!

5 0

3 years ago

Question is attached as image, please help :>

harkovskaia [24]

Answer:

Proved

Explanation:

Given

$X = (a.\bar b)+(\bar a.b)$

$(a + b)\ .$ $\frac{}{a.b}$

Required

Find out why they represent the same

To do this, we simplify either $(a + b)\ .$ $\frac{}{a.b}$ or $X = (a.\bar b)+(\bar a.b)$

In this question, I will simplify $(a + b)\ .$ $\frac{}{a.b}$

Apply de morgan's law

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $(a + b) . (\bar a + \bar b)$

Apply distribution property

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $a.\bar a + a.\bar b + \bar a . b + b . \bar b$

To simplify, we apply the following rules:

$a.\bar a = 0$ --- Inverse law

$b.\bar b = 0$ --- Inverse law

So, the expression becomes

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $0 + a.\bar b + \bar a.b + 0$

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $a.\bar b + \bar a.b$

Rewrite as:

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $(a.\bar b)+(\bar a.b)$

From the given parameters:

$X = (a.\bar b)+(\bar a.b)$

This implies that:

$(a + b)\ .$ $\frac{}{a.b}$ when simplified is X or $(a.\bar b)+(\bar a.b)$

3 0

3 years ago