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arsen [322]
3 years ago
5

Siân is saving for a car which costs 11 800 AUD. Find how many years it will take for the value of the investment to reach this

value. Round to the nearest year.
Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

<em>The question is incomplete as the invested amount and the interest rate are not given. However, I will give a general method of solving it.</em>

<em>Assume that:</em>

<em></em>r = 5\%<em> --- interest rate</em>

<em></em>PV =9000<em> --- Present value or invested amount</em>

<em></em>

<em>To calculate time (in years), we make use of the following formula of future value</em>

<em></em>FV = PV(1 + r)^n<em></em>

<em>Where</em>

<em></em>FV = 11800<em></em>

<em></em>

<em>So:</em>

<em></em>11800 = 9000( 1 + 5\%)^n<em></em>

Divide both sides by 9000

<em></em>1.31 = ( 1 + 5\%)^n<em></em>

<em></em>

<em>Take logarithm of both sides</em>

<em></em>Log(1.31) = Log(1 + 5\%)^n<em></em>

<em></em>

<em>Apply law of logarithm</em>

<em></em>Log(1.31) = nLog(1 + 5\%)<em></em>

<em></em>

<em>Make n the subject</em>

<em></em>n = \frac{Log(1.31)}{Log(1 + 5\%)}<em></em>

<em></em>

<em>Express 5% as decimal</em>

<em></em>n = \frac{Log(1.31)}{Log(1 + 0.05)}<em></em>

<em></em>n = \frac{Log(1.31)}{Log(1.05)}<em></em>

<em></em>n = \frac{0.1173}{0.0212}<em></em>

<em></em>n \approx 6<em></em>

<em>The time to reach the future value is approximately 6 years.</em>

Use the above explanation to answer your question

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