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3 years ago

Choose ONE of the equations to solve. SHOW DETAILED WORK & give the answer.

Mathematics

2 answers:

Elis [28]3 years ago

6 0

Answer:

x=3

Step-by-step explanation:

9x+5+2x = 38

Combine like terms

9x+2x +5 = 38

11x+5 = 38

Subtract 5 from each side

11x+5-5 = 38-5

11x = 33

Divide each side by 11

11x/11 = 33/11

x = 3

Sindrei [870]3 years ago

3 0

Answer:

3(2n + 10) = 54

n = 4

Step-by-step explanation:

3(2n + 10) = 54

Divide both sides by 3

2n + 10 = 18

Subtract 10 form both sides

2n = 8

Divide both sides by 2

n = 4

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-3|-5|+2x-1. WILL MARK BRAINLIEST.

matrenka [14]

Answer:

2(X-8)

Step-by-step explanation:

-3|-5|+2x-1

|-8|+2x-1

2(x-8)

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3 years ago

¿Cuál es el valor de la razón de cambio cuando tenemos un vaso con agua a temperatura ambiente al congelador por 15 minutos?

grandymaker [24]

Answer: $2 \°C/min$

Step-by-step explanation:

The rate of change is a measure in which one variable is modified in relation to another. In this case we have the variables:

Temperature in $\°C$

Time in $min$

Now, to calculate the rate of change, we have to divide one variable by the other. In this case the change in temperature $\Delta T$ divided by the time variation $\Delta t$ .

Hence, assuming the ambient temperature of the glass is $30 \°C$ and the elapsed time $15 min$ we have:

$\frac{\Delta T}{\Delta t}=\frac{30 \°C}{15 min}=2 \frac{\°C}{min}$

5 0

4 years ago

Express 30 km/h in m/s

n200080 [17]

Given - 30Km/hr

soution,

we know that

1 km = 1000 m

1 hr = 3600 second

Now

30km/hr = 30×1000÷3600

30Km/hr = 8.34 m/s

Answer - 8.34 m/s

5 0

3 years ago

100 POINTS! I WILL MARK BRAINLIEST. ONLY ANSWER IF YOU KNOW HOW TO DO IT. RANDOM ANSWERS WILL BE REPORTED! :)

8090 [49]

Answer:

the cords are 4 -2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Simplify the expression. 4 + 5\3^2 - 2^2 <br> A) -3 <br> B) -5 <br> C) 5 <br> D) 9\5

DedPeter [7]

Answer:

Step-by-step explanation:

$\frac{4+5}{3^{2}-2^{2}}=\frac{9}{9-4}\\\\=\frac{9}{5}$

4 0

3 years ago