Question

Find the value of cos J rounded to the nearest hundredth, if necessary.

Answer 1

$\green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}}$

Find the value of cos J rounded to the nearest hundredth

$\bold{ \red{\star{\blue{GIVEN }}}}$

HYPOTHESES= 13

PERPENDICULAR= 12

BASE = ?

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

$\cos(j) = ?$

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

1. PYTHAGORAS THEROM
2. $\cos(j) = \frac{ BASE}{HYPOTENUSE}$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

FOR BASE:-

${h}^{2} = {p}^{2} + {b}^{2}$

${13}^{2} = {12}^{2} + {x}^{2} \\ 169 - 144 = {x}^{2} \\ 25 = {x}^{2} \\ \sqrt{25} = x \\ 5 = x = base$

NOW :-

$\cos(j) = \frac{ BASE}{HYPOTENUSE}$

$\cos(j) = \frac{5}{13} \\ \cos(j) = 0.34$

Answer 2

Answer:

cosJ ≈ 0.38

Step-by-step explanation:

This is a 5- 12- 13 right triangle

with HI = 12, HJ = 13, IJ = 5

cosJ = $\frac{adjacent}{hypotenuse}$ = $\frac{IJ}{HJ}$ = $\frac{5}{13}$ ≈ 0.38 ( to nearest hundredth )