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GenaCL600 [577]
2 years ago
14

175 calories in 12 ounces. how many in 1 ounce?​

Mathematics
2 answers:
qaws [65]2 years ago
7 0

Take a ratio

175 : 12

   x : 1

175 x 1 = 12x

175/12=x

x= 14.58

14.58 calories in 1 ounce

kaheart [24]2 years ago
6 0

Answer:

I think its 14.58

Step-by-step explanation:

luv you

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weqwewe [10]
Were in the same grade
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2 years ago
Manny is an online student who currently owns an older car that is fully paid for. He drives, on average, 110 miles per week to
Step2247 [10]

Answer:

The new car costs more

Old car = $5062.125

New car = $7161.357

Step-by-step explanation:

Manny drives an average of 110 miles per week with his old car. The old car gets 16 miles per gallon. The cost per gallon is $2.65 repair and Maintainance costs an average of $740 per year.

For the old car, to find the amount spent on the car we have

110/16 * 2.65 = $18.21875 / week

There are 52 weeks in a year. We have

10.21875*52 = $ 947.375

947.375 + 740

= $1687.375

= 1687.357 * 3

= $5062.125

The new car cost $6500 over a three year loan process.

The car gets 28 miles per gallon. It requires a maintenance f $10 per month. For the new car to find the amount, we have

110*28 * 2.65 *52 = $541.357

541.357 + 10(12) + 6500

= $7161.357

5 0
2 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
2 years ago
Find the unit price. 14 ounces of canned corn for $1.96 ​
MakcuM [25]
$27.44 USD. Would be the correct answer.
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2 years ago
A man 50 years old has 8 sons born of equal intervals. The sum of the ages of the father and sons is 186. What is the age of the
Rudiy27
<span>let x be the interval, then: 186 = 50 + 3 + (3+x) + (3+2x) + (3+3x) + (3+4x) + (3+5x) + (3+6x) + (3+7x) 186 = 74 + 28x x = 4 Eldest son age = 3+7x = 3+28 = 31.</span>
8 0
3 years ago
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