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N76 [4]
3 years ago
14

When do you use a for loop instead of a while loop?

Computers and Technology
1 answer:
creativ13 [48]3 years ago
8 0

Answer:

i dont know.prob guess a short loop.

Explanation:

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In order to be compliant with the NIST publications, policies must include key security control requirements. One of these key r
lesya692 [45]

Answer:

True

Explanation:

In order to be compliant with the NIST publications, policies must include key security control requirements. One of these key requirements includes certification and accreditation, which is a process that occurs after the system is documented, controls tested, and risk assessment completed. It is required before going live with a major system. Once a system is certified and accredited, responsibility shifts to the owner to operate the system is a true statement.

8 0
3 years ago
Help ASAP
Gelneren [198K]

Answer:

By supplying a variety of charts and graphs to present the information in best way.

By tracking and analyzing the data

By conveying large amount of numerical data in more understandable format.

Explanation:

You need to know the limitations of Excel software. You will find that it does not support more than 3 variables while analyzing. However, if you use analytic software like Tableau and Microsoft Power BI then you can use a lot number of variables. And this is done through graphs and charts, and the other variables apart from x, y, z are the colors, shades. etc. Even color alone can add a good number of variables, and hence you can understand. Thus, you will be able to query better. Queries become better if you have more variables. And charts and graphs always present the information in the best way/ Also you can track and analyze the data. And through it conveying a large amount of numerical data in a more understandable format is made possible, and this is definitely quite helpful. Hence, all of the options mentioned above are helpful. But they do not do complex calculations and complex queries in fact.

4 0
3 years ago
Read 2 more answers
Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr
drek231 [11]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

 

Hence the output is:

The (shortest) distance between the cars is: 222.56        

3 0
3 years ago
The Sleeping-Barber Problem:
s2008m [1.1K]

Answer:

Explanation:

Following are the Semaphores:

Customers: Counts waiting customers;

Barbers: Number of idle barbers (0 or 1)

mutex: Used for mutual exclusion.

Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves

Shared data variable:

count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.

// shared data

semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;

int count_cust= 0;

void barber() {

while(true) { //shop is always open

wait(customers); //sleep when there are no waiting customers

wait(mutex); //mutex for accessing customers1

count_cust= count_cust-1; //customer left

signal(barbers);

signal(mutex);

cut_hair();

}

}

void customer() {

wait(mutex); //mutex for accessing count_cust

if (count_cust< n) {

count_cust= count_cust+1; //new customer

signal(customers); signal(mutex);

wait(barbers); //wait for available barbers get_haircut();

}

else { //do nothing (leave) when all chairs are used. signal(mutex);

}

}

cut_hair(){ waiting(cutting);

}

get_haircut(){

get hair cut for some time; signal(cutting);

}

6 0
3 years ago
Which best describes a paraphrase?
Anna11 [10]
To rewrite something , but in your own words
4 0
3 years ago
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