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3 years ago

Absolute value /-3/-/-2/=

Mathematics

1 answer:

Anni [7]3 years ago

8 0

Answer:

I think it is 1

Step-by-step explanation:

You might be interested in

Given that f(x) = 2x − 5, find the value of x that makes f(x) = 15

liraira [26]

Answer:25

Step-by-step explanation:2(15)-5 gives u the value of 25

8 0

2 years ago

Divide to find two equivalent fraction 4/12

SCORPION-xisa [38]

Answer: 2/6 and 1/3

Step-by-step explanation: Equivalent fractions are fractions that have the same value but have different top and bottom numbers.

We can find 1 equivalent fraction by dividing the numerator and the denominator by 2 and we get 2/6. We can also reduce 2/6 by dividing the numerator and the denominator by 2 and we get 1/3.

So two equivalent fractions for 4/12 would be 2/6 and 1/3.

4 0

3 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

Simplify.<br> 8^15 : 8^-3<br> asap please

torisob [31]

Answer:

$8^1^5 = 3.5184372e+13\\8^-^3=0.001953125.$

Step-by-step explanation:

hope this helps.

3 0

2 years ago

Read 2 more answers

The principal P is borrowed and the loan's future value A at time t is given. Determine the loan's simple interest rater.

Anni [7]

Interest rate = 7%

I= PRT where I is the interest earned, p is the principal, r is rate as a decimal, and t is time in years.

A - P will give us the interest earned.

12,150 - 9,000 = 3,150

3150 = (9000)(r)(5)
3150 = 45,000r
r = 0.07
r = 7%

4 0

3 years ago