Answer:
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Explanation:
<h2>i dont know what your talking about im onyl 12</h2>
Combustion of Fossil Fuels
Explanation:
The combustion of fossil fuels is a major contributor to unbalancing of the carbon cycle which causes more carbon dioxide to be released into the air than can be naturally processed.
Combustion of fossil fuel is an anthropogenic source of carbon dioxide emission. This chemical process is used to power internal combustion engines and industrial activities. The by product is usually carbon dioxide.
Plants that use carbon dioxide for their life processes cannot completely absorb all of this anthropogenic emission.
Naturally, animal respiration and decomposition provides enough carbon dioxide for use during photosynthesis. Combustion of fossil fuels tips this balance.
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Using the equation PV = nRT
Therefore; V = nRT / P
Need moles of glucose converted to moles of the product gas (CO2).
Molecular weight calculation:
C 6 X 12.01 = 72.06
H 12 X 1.01= 12.12
O 6 X 16.00 = 96.00
sum = 180.18
25.5 g of C6H12O6 ( 1 mol C6H12O6 / 180.18 g) ( 6 mol CO2 / 1 mol C6H12O6) =
0.84915 mol CO2 gas.
Convert temp: 37 °C + 273.15 = 310.15 K
V= ((0.84915 mol)× (0.0821 L atm / mol K) (310.15 K))/0.980 atm
V = 22.0635 L
= 22.06 L CO2
Calculate its molar solubility in a saturated aqueous solution that is also 0.050 M in fluoride ion, F-. Ksp = (x)(2x + 0.05)2. 2x = 4.210 4
Answer:
0.371
Explanation:
number of moles = mass / Ar
= 23.8g / 32.1 + (16.0 × 2)
= 0.37129485179 = 0.371 (3 s.f).
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