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3 years ago

Question 8 (1 point)

Chemistry

1 answer:

Margaret [11]3 years ago

5 0

Combustion of Fossil Fuels

Explanation:

The combustion of fossil fuels is a major contributor to unbalancing of the carbon cycle which causes more carbon dioxide to be released into the air than can be naturally processed.

Combustion of fossil fuel is an anthropogenic source of carbon dioxide emission. This chemical process is used to power internal combustion engines and industrial activities. The by product is usually carbon dioxide.

Plants that use carbon dioxide for their life processes cannot completely absorb all of this anthropogenic emission.

Naturally, animal respiration and decomposition provides enough carbon dioxide for use during photosynthesis. Combustion of fossil fuels tips this balance.

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What factors influence the gravitational forces between objects?

lisabon 2012 [21]

Explanation:

F = k.m1.m2/r²

m1 and m2: masses of objects

r: distance between the objects

k: a constant

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3 years ago

Of the following substances, ________ has the highest boiling point. Of the following substances, ________ has the highest boili

kolezko [41]

Answer:

Of the following substances, <u>PCl₃</u> has the highest boiling point

Explanation:

The given substances and their boiling point from online resources are;

Krypton, Kr, boiling point = -153.4°C

Chlorine gas, Cl₂, boiling point = -34.6°C

Borane, BH₃, (transient compound), boiling point of the dimer it forms B₂H₆ = -164.85°C

Methane, CH₄, boiling point = -161.6°C

Phosphorus trichloride, PCl₃, boiling point = 76.1°C

Therefore, given that PCl₃ is a volatile liquid at room temperature, while the other substances are gases and that PCl₃ has the highest boiling point of all the substances of 76.1°C, the substance with the highest boiling point is PCl₃.

5 0

2 years ago

How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M?

satela [25.4K]

3.5 M has 3.5 moles per litre
so we have one litre, so we need 3.5 moles
moles = mass/molarmass
3.5 * 23 = 80.5

5 0

3 years ago

Read 2 more answers

If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated

Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:

$\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution

$\Delta T^o$ = freezing point of water

i = Van't Hoff factor

$K_f$ = freezing point constant

m = molality

$w_b$ = mass of solute

$w_a$ = mass of solvent

$M_b$ = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0

3 years ago

Gerald's science teacher mixed liquid X and liquid Y, both at room-temperature, in a large beaker. two beakers of clear solution

Pachacha [2.7K]

Answer:

the answer is C

Explanation:

7 0

3 years ago

Read 2 more answers