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erica [24]
3 years ago
8

Find the slope of the line.

Mathematics
2 answers:
Bess [88]3 years ago
8 0
The slope is 1/3 because slope is rise over run so you go up one unit and go right three units.
tatyana61 [14]3 years ago
3 0

Answer:

The slope is 1/3

Step-by-step explanation:

Slope is rise over run. Starting from the point (1,-4), the line moves up one unit (rise=1) and then 3 units to the right (run=3) to get to the point (4,-3). Therefore rise over run, or the slope, is 1/3.

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What is the Factor 4m^3-32n^3
Klio2033 [76]

Answer:

2(47m^3-16n^3)

Step-by-step explanation:

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3 years ago
Which of the following is true?
EleoNora [17]
The options can be rewrited as follow:
A. 5<4
B. 5<5
C. 5<4
D. 4<-5

∴ Answer is none of the above.

Unless perhaps you have written down the question incorrectly.
8 0
3 years ago
PLEASE HELP ME THIS IS SO IMPORTANT
Leni [432]

Answer:I believe it is (C) I’m not 100% sure but I think so

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
There are 10 multiple choice questions in an examination. first 4 have 5 choices each and remaining have 4 choices each. how man
stira [4]

2560000 sequences of answers are possible.

<em><u>Explanation</u></em>

Total number of questions = 10

First 4 questions have 5 choices each and remaining (10-4)= 6 questions have 4 choices each.

So, the possible sequences of answers for first 4 questions = 5^4 = 625

and the possible sequences of answers for remaining 6 questions = 4^6=4096

Thus, the total possible number of sequences of answers = (625 × 4096) = 2560000

5 0
3 years ago
Read 2 more answers
he​ half-life for a link on a social network website is 2.6 hours. Write an exponential function T that gives the percentage of
pychu [463]

Answer:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining= [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

Step-by-step explanation:

Previous concepts

The half-life is defined "as the amount of time it takes a given quantity to decrease to half of its initial value. The term is most commonly used in relation to atoms undergoing radioactive decay, but can be used to describe other types of decay, whether exponential or not".

Solution to the problem

The half life model is given by the following expression:

A(t) = A_o (1/2)^{\frac{t}{h}}

Where A(t) represent the amount after t hours.

A_o represent the initial amount

t the number of hours

h=2.6 hours the half life

And we want to estimate the % after 5.5 hours. On this case we can begin finding the amount after 5.5 hours like this:

A(5.5) = A_o (1/2)^{\frac{5.5}{2.6}}

Now in order to find the percentage relative to the initial amount w can use the definition of relative change like this:

% Remaining = \frac{|A_o - A_o(1/2)^{\frac{5.5}{2.6}}|}{A_o} x100

We can take common factor A_o and we got:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining = [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

5 0
3 years ago
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