Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
the radius: r^2 = 81
r =9
c = 2*pi*r
= 2 * pi * 9
= 18 *pi
Answer: 18*pi or approximately 56.62
Answer: b=101 c=79 d=101
Step-by-step explanation:
since it is a parallelogram opposite angels are congruent a = c ad b=d
because we know a=79 c must equal 79
and because all the angles must add up to 360 add 79+79 = 158
then subtract from 360- 158= 202 then divide by 2 and this will give us the value for b and d b,d=101
Solution:
Given:
Using the simple interest formula,
Therefore, the simple interest is $960.
Answer:
9.5
Step-by-step explanation:
(0.5^2 + 0.5^-2 + 0.5) / 0.5 = 9.5
Hope this help! :)
