Answer:
25%
Step-by-step explanation:
125 of 500 can be written as: 125
/500
To find a percentage, we need to find an equivalent fraction with the denominator 100. Multiply both numerator & denominator by 100.
125
/500 × 100
/100
= (
125 × 100/
500
) × 1
/100 = 25
/100
This question is incomplete
Complete Question
An arts academy requires there to be 6 teachers for every 132 students and 4 tutors for every 44 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 132 students?
Answer:
a)How many students does the academy have per teacher?
22 students per teacher
b) Per tutor?
11 students per tutor
c) How many tutors does the academy need if it has 132 students?
12 tutors
Step-by-step explanation:
a)How many students does the academy have per teacher?
6 teachers = 132 students
1 teacher = x
6 × x = 132 × 1
x = 132 × 1/6
x = 22 students
Hence, we have 22 students per tutor
b) Per tutor?
4 tutors = 44 students
1 tutor = x students
Cross Multiply
4 × x = 1 × 44
x = 44/4
x = 11 students
Hence, we have 11 students per tutor
c) How many tutors does the academy need if it has 132 students?
44 students = 4 tutors
132 students = x tutors
Cross Multiply
44 × x = 132 × 4
44x = 132 × 4
x = 132 × 4/44
x = 12 tutors
The academy needs 12 tutors if they have 132 students.
Answer:
I can even see anything can you reupload your answer, please?
Step-by-step explanation:
Step-by-step explanation:
Answer:
The interval of decrease is 0 ≤ x ≤ 1.25
Step-by-step explanation:
First, we have to find the point where it changes from increasing to decreasing or decreasing to increasing.
The graph shows that there is a decrease before 1.25 h, and it increases after 1.25 h also.
We can further prove that 1.25 is the point of change when we enter 1.25 in place of t in the given equation
d(1.25) = 40|1.25 - 1.25| = 0
We see that the graph is decreasing before 1.25, so the interval will have to end at 1.25.
We also see that there is no increase before 1.25, so we can make the interval begin at 0