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kari74 [83]
3 years ago
11

Pls help :(((((((((((((

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

79,514

Step-by-step explanation:

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6+8d=7d solve for d.
Margarita [4]

Question -

6 + 8d = 7d

Solution-

6. = 7d - 8d

6. = -d

d. = -6

<h3>Verification </h3>

6 + 8(-6) = 7(-6)

6 - 48. = -42

-42. = -42

LHS= RHS

Hence value of d is -6

hope it helps

4 0
3 years ago
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What is the relationship between the 5’s in 345,502
Wittaler [7]
The answer is to the question is C
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You are running a concession stand at a basketball game. You are selling hot dogs and sodas. Each hot dog costs $2.25 and each s
baherus [9]

The equations and the number of hotdogs and sodas sold are:  x+ y = 126 and 2.25x + 1.50y = 225.75 ; 49 hot dogs and 77 sodas.

Two equations can be derived from this question:

2.25x + 1.50y = 225.75 equation 1

x + y = 126 equation 2

Where:

x = number of hotdogs sold

y = number of soda sold

In order to determine the value of y, multiply equation 2 by 2.25

2.25x + 2.25y = 283.50 equation 3

Subtract equation 1 from 3

57.75 = 0.75y

y = 77

Substitute for y in equation 2

x + 77 = 126

x = 49

To learn more about simultaneous equations, please check: brainly.com/question/23589883

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3 years ago
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Find the distance between the points (-7, -10) and (-5, -1)
julsineya [31]
Find the Distance Between Two Points
Use the distance formula to determine the distance between two points.
Exact Form:
√85

Decimal Form:
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7 0
2 years ago
Bread and sugar cost 110 together,bread cost 100 more than sugar,how much does sugar cost?
dangina [55]
First write an equation system based on the problem
We can write "<span>Bread and sugar cost 110 together" as
</span>∴ b + s = 110
We can write "<span>bread cost 100 more than sugar" as
</span>∴ b = 100 + s
<span>
Second, solve the equation system by subtitution method
Subtitute b with (100+s) in the first equation, and we'll find the value of s
b + s = 110
(100 + s) + s = 110
100 + 2s = 110
2s = 110 - 100
2s = 10
  s = 10/2
  s = 5
The cost of the sugar is 5</span>
4 0
3 years ago
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