Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
The probability at being stopped at exactly one light is 1-0.18-0.28=.54 or 54%.
Answer:
x = - 8/23
y = 40/23
Step-by-step explanation:
-5x- y = 0
and
-8x+3y = 8
The first step to solve this would be to get what one of the two variables equal. The easiest in this case is y from the first equation.
-5x-y = 0
-y = 5x
y = - 5x
Now you can take this y value and plug it into the section equation.
-8x + 3(-5x) = 8
-8x - 15x = 8
-23x = 8
x = - (8/23)
Once you get the x value you can plug it back into equation one to get y's value
-5*-(8/23) - y = 0
40/23 - y = 0
y = 40/23
I believe the physical properties are boiling point, freezing point, and water vapor.
Answer:
On average, the scores of Class B are lower than Class A.
hope this helps
Step-by-step explanation:
