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a_sh-v [17]
3 years ago
9

What is the smallest unit of measurement?

Mathematics
2 answers:
Step2247 [10]3 years ago
7 0
I think it's the Planck length. You can define a unit smaller than that, but it can't exist.
kvasek [131]3 years ago
3 0
The smallest unit of measure is the millimeter

Hope this helps ;)
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Imogene invested $8,000 in a bank account that pays 8 percent simple interest at the end of each year. Her friend invested the s
Natali5045456 [20]

The right system of equations to describe the situation would be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of Imogene and her friend respectively at the end of t years.

Now for the value of amount earned, y1 and y2:

y1=8000*0.08

y2=2000*√(t-2)

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5 0
3 years ago
Jane , Andre and Maria picked 840 pounds of apples. Andre picked 3 times as many as Maria. Jane picks 2 times as many as Andre.
Galina-37 [17]
To answer the problem, let x be the number of apples Maria picked. By this representation, the number of apples Andre picked is 3x and that Jane picked 6x apples. The sum of all apples picked is 840. The equation that represent the situation is,
 
                                 x + 3x + 6x = 840   ; x = 84 

Andre picked 3x apples. Thus, Andre picked 252 apples. 

3 0
3 years ago
3. A teacher made a copy of a map. To make the map easier to see, the teacher enlarged the area of the map by 38%. Let d represe
____ [38]

Answer:

1.38d

Step-by-step explanation:

4 0
2 years ago
Plss help me<br><br> NO LINKS
Degger [83]

Answer:

17 square yards

Step-by-step explanation:

split it so you have a big rectangle and a small one. find the areas of both

the big one was 5(3)= 15, the second was 1(2)=2. add those together.

5 0
2 years ago
Read 2 more answers
Find the limit. (If an answer does not exist, enter DNE.) lim Δx→0 (x + Δx)2 − 3(x + Δx) + 2 − (x2 − 3x + 2) Δx
yawa3891 [41]

\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}

Expand the numerator as

x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2

Then in the limit,

\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}

3 0
2 years ago
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