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kati45 [8]
3 years ago
13

Find the area of the trapezoid 14.5 8 19.5​

Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0

Step-by-step explanation:

Which one is the height?¿

The formula is

b1+b2 divided by 2 times the height

That's the best I can do for you atm atleast.

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What is 58% of 18 <br>can you please help and explian how u got it​
aleksklad [387]
To obtain 58 percent of 18 multiply 18 by 0.58, because 58 percent is equal to 58/100. That said, your result rounded to two decimals is 10.44.

This answers what is 58% of 18. If you have a currency, such as in the case of 18 dollars, proceed as outlined in the example right below.
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3 years ago
Which property explains why these two expressions are equal?
STALIN [3.7K]
The correct answer is letter S
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70 POINTS !! Charlotte has a map of the village. The scale on the map is such that 1cm represents 25m.
Natasha_Volkova [10]

Answer:

A. 175 m

B. 20 cm

Step-by-step explanation:

\frac{1 cm}{25 m} =\frac{7 cm}{x m}

x = 175 m

\frac{25 m}{1 cm} = \frac{500 m}{x cm}

x = 20 cm

5 0
2 years ago
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mariarad [96]

Answer:

5 + 1.50x=15.50

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Step-by-step explanation:

Let x be the number of movies rented

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7 0
3 years ago
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Planners of an experiment are evaluating the design of a sphere of radius r that is to be filled with helium (0°c, 1 atm pressur
Vikentia [17]
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3 
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3 
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3) 
The density of silver is 10.5g/cm^3 
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2) 

Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3 

Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2) 
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
6 0
3 years ago
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