An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).
The equation for an arithmetic sequence is
is the "n-th" number in the sequence (ex: is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so
<span>d=-2 because the question gives you that
</span>
<span>
</span><span>
</span><span>
</span><span>
</span>
The answer is A. -9.
<u> </u>
<span>The answer is C. 158</span>
For the second one, it gives you
and <span>
You can use this to find d
</span><span>
</span><span>
</span><span>
</span><span>
</span><span>
</span><span>
</span>
Now you can just solve using the equation normally.
<span>
</span><span>
</span><span>
</span><span>
</span><span>
</span>
The answer is C. 158
Answer:
Correct option: (a) 0.1452
Step-by-step explanation:
The new test designed for detecting TB is being analysed.
Denote the events as follows:
<em>D</em> = a person has the disease
<em>X</em> = the test is positive.
The information provided is:
Compute the probability that a person does not have the disease as follows:
The probability of a person not having the disease is 0.12.
Compute the probability that a randomly selected person is tested negative but does have the disease as follows:
![P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%29%3DP%28X%5E%7Bc%7D%7CD%29P%28D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%20P%28D%29%5C%5C%3D%5B1-0.97%5D%5Ctimes%200.88%5C%5C%3D0.03%5Ctimes%200.88%5C%5C%3D0.0264)
Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:
![P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%5E%7Bc%7D%29%3DP%28X%5E%7Bc%7D%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%7B1-%20P%28D%29%5D%5C%5C%3D0.99%5Ctimes%200.12%5C%5C%3D0.1188)
Compute the probability that a randomly selected person is tested negative as follows:
Thus, the probability of the test indicating that the person does not have the disease is 0.1452.
Answer:
$500 and $2000
Step-by-step explanation:
Let x represent the total investment = $2500
also, this total is split into two different funds
Lets represent these funds as a and b, such that fund a yields a profit of 3% and fund b yield a profit of 5%
So,
a + b = x
a + b = 2500 ......eq 1
Profit from each fund gives;
0.03 a + 0.05b = 115 ....eq 2
Solve simultaneously using substitution method
From eq 1;
b = 2500 - a
Slot in this value in eq 2
0.03a + 0.05 (2500 - a) = 115
expand
0.03a + 125 - 0.05a = 115
collect like terms
0.03a - 0.05a = 115 - 125
-0.02a = -10
Divide both sides by -0.02
a = $500
Put this value of a in eq 1
500 + b = 2500
Subtract 500 from both sides
b = 2500 - 500
b = $2000
Answer:
the answer is 1
Step-by-step explanation:
Using the given functions, it is found that:
- Lower total cost at Jump-n-Play: 40, 64.
- Lower total cost at Bounce house: 28, 8, 30.
- Same total cost at both locations: 32.
<h3>What are the cost functions?</h3>
For n visits to Jump-n-play, the cost is:
J(n) = 189 + 3n.
For n visits to Bounce Word, the cost is:
B(n) = 125 + 5n.
Comparing them, we have that:
Hence:
- For less than 32 visits, the cost at Bounce World is lower.
- For more than 32 visits, the cost at Jump-n-play is lower.
Hence:
- Lower total cost at Jump-n-Play: 40, 64.
- Lower total cost at Bounce house: 28, 8, 30.
- Same total cost at both locations: 32.
More can be learned about functions at brainly.com/question/25537936
