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Lera25 [3.4K]
3 years ago
10

What is the area of this trapezoid? Enter your answer in the box.

Mathematics
2 answers:
olga2289 [7]3 years ago
4 0
The formula for area of a trapezoid is
\frac{(b1 + b2) \times h}{2}
so you add up the bottom base (17) and the top base (3) to get 20.
you then take the sum of the bases (20) times the height (8) to get 160.
lastly, you take 160 ÷ 2 to get your final answer, which is 80 (:
Anna35 [415]3 years ago
4 0

Answer:

80

Step-by-step explanation:

i took it in the k12 lesson so the answer is 80

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Enter the equation of the line in slope-intercept form.
vitfil [10]

Answer:

y=\frac{1}{4}x

Step-by-step explanation:

the y intercept is 0

4 0
3 years ago
Is h(x) = 6 a linear function and why
Andrei [34K]

Answer:

yes, absolutely. specifically it's a horizontal line at 6.

6 0
2 years ago
Which point on the number line is the best approximation for √59?
Elina [12.6K]

Answer:

6^2 = 36

Step-by-step explanation:

The number that best approximates the square of 6 is 36, its actual value. The point so labelled is the appropriate point on the number line.

7 0
2 years ago
Tickets for a dance recital cost $15 for adults and $7 for children. The dance company sold 253 tickets, and the total receipts
elixir [45]

Answer:

Adult tickets =125

Child tickets = 128

Step-by-step explanation:

Let the number of adult and children tickets sold be x and y respectively

So that

x+y= 253--------1

Since total sales/receipt is $2,771

And given that tickets for a dance recital cost $15 for adults and $7 for children hence

15x+7y= 2771-------2

Solving equation 1 and 2 simultaneously we have

x+y= 253---------------1

15x+7y= 2771----------2

Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3

15x+15y=3795---------3

-{15x+7y= 2771----------2

0+8y=1024

8y= 1024

y= 1024/8

y= 128 tickets

So solve for x let us put y= 128 in equation 1

x+ 128=253

x=253-128

x= 125 tickets

8 0
3 years ago
The ordered pair (1, -2) is a solution to the system of linear equations.
vesna_86 [32]

Answer:

False

Step-by-step explanation:

2x + y = 0

Try (1, -2)

2(1) + (-2) = 0

2 + (-2) = 0

0 = 0

The solution works on the first equation.

-x + 2y = 5

-(1) + 2(-2) = 5

-1 - 4 = 5

-5 = 5

The solution does not work in the second equation.

Answer: False

3 0
3 years ago
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