There are 2 possibilities for where A can be: one where C is 30° (and A is 60°) and another where C is 60° (and A is 30°). Since it's not specified, we can find both.
30°:
drawing the triangle on a graph, you can see that point C is 4 units above point B, so we know that one side of the triangle is 4. Once we find the other "leg" of the triangle (the one that's parallel to the x-axis), we can just add that value to B to find the x coordinate of A.
If angle C is 30°, using the side ratios of a 30-60-90 triangle, that side is "a√3", and the side we're looking for is a. So, to find a, we just divide 4 by √3. In that case, point A is 4/(√3) units to the right of -2√3. We can rationalize 4/(√3) like this:
(4√3)/3
and then add that to 2√3:
(4√3)/3 + -2√3
(4√3)/3 + (-6√3)/3 = (-2√3)/3
We know that the x-coordinate of A is (-2√3)/3, and the y-coordinate is -1 because B is a right angle and we're just moving horizontally. So, if C is 30° and A is 60°, point A is at ((-2√3)/3, -1).
60°:
in this case, the leg we know is "a" and the leg we're looking for is "a√3". So, we can multiply 4 by √3 to get the distance from B:
4 x √3 = 4√3
4√3 + -2√3 = 2√3
So the x-coordinate of A here is 2√3, and the y-coordinate is still -1: (2√3, -1).
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Answer:
B. y=3x+12
Step-by-step explanation:
Hi there!
We want to find out which equation is equivalent to -6x+2y=24
The equation is currently written in standard form, which is ax+by=c, where a, b, and c are integer coefficients, but a and b CANNOT equal zero
We can change the equation into slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept, as all of the answer options are in slope-intercept form.
To do that, we'll need to isolate y by itself on one side
So let's add 6x to both sides to remove it from the left side
-6x+2y=24
+6x +6x
__________________
2y=6x+24
Now divide both sides by 2 to get the value of y by itself (1y)
y=3x+12
The answer is B. y=3x+12
Hope this helps!
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: mark obtained in an aptitude test by a candidate.
This variable has a mean μ= 128.5 and standard deviation σ= 8.2
You have the data of three scores extracted from the pool of aptitude tests taken.
148, 102, 152
The average is calculated as X[bar]= Σx/n= (148+102+152)/3= 134
I hope this helps!
Answer:
Step-by-step explanation:
Well first you have to find the dimensions of the frame, you can find that by subtracting the dimensions of the photo from the whole dimensions so it will be the
length of the photo and frame - length of the photo = 25- 20 = 5 length of the frame
Now the width of the photo and frame - width of the photo = 20 -16 = 4 the width of the frame
ok so the Area of the rectangle = width x length = 4 x 5 = 20 the Area of the frame
Hope that helps