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1 year ago

15

On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite

1 answer:

Liono4ka [1.6K]1 year ago

8 0

Answer:

b = -a

Step-by-step explanation:

Since a and b are equally distant to zero but in opposite directions, a and b are opposites, or additive inverses.

The sum of additive inverses is zero.

a + b = 0

b = -a

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there are 36 roses and 27 carnations. anna is making flower arrangements using both flowers, if she made the maximum number of a

solniwko [45]

This is a GCF problem,
find the GCF of 36 and 27. To do this, list out the factors for each number.
EX 36- 1×36, 2×18, so on and so on. Then do this for 27. The GCF will be the greatest factor. In this case, that is 9.
So there would be 9 groups because that is the greatest common factor.
there would be 4 roses in each group because 4×9= 36.
There are 3 carnations in each group because 9×3 =27.
So 9 groups with 4 roses and 3 carnations.

4 0

3 years ago

Approximate the value of 5 π

olya-2409 [2.1K]

Answer with explanation:

→π is an Irrational Number.

→Decimal Representation of π is non terminating non repeating.

$\pi=\frac{\text{Circumference of Circle}}{\text{Diameter}}\\\\\pi =3.14\\\\ 5\pi =5 \times 3.14=15.70$

⇒5 π =15.70

8 0

2 years ago

Read 2 more answers

Hisako sells dolls at her doll store. If she sells a doll for $35, and there is 6% sales tax, what is the tax amount a customer

Sloan [31]

Given:

The price of a doll = $35

Sales tax = 6%

To find:

The tax amount that a customer will pay on one doll.

Solution:

The price of doll is $35 and the sales tax is 6%, so the tax amount on a doll is 6% of 35.

$\text{Tax amount}=35\times \dfrac{6}{100}$

$\text{Tax amount}=\dfrac{210}{100}$

$\text{Tax amount}=\dfrac{21}{10}$

$\text{Tax amount}=2.1$

Therefore, the tax amount that a customer will pay on one doll is $2.1.

7 0

2 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

3 years ago

HELP!! Given f(x)=5x squared and g(x) = x squared + 2x squared - 5x, what is F (x) * g(x)?

TEA [102]

X^2+2x^2-5x

((x^2)+2x^2)-5x

Pull the factors out

3x^2-5x=x(3x-5)

x(3x-5)

x(3x-5)*5x^2

5x(3x-5)*x^2

Final

5x^3*(3x-5)

8 0

2 years ago