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3 years ago

Urgently need help!!! I will mark the best answer as BRAINLIEST!!!!!

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

3 0

C. 16.4

Step-by-step explanation:

The formula to apply here is;

A=P(1+r/n) ^nt where

A=final amount

P=starting amount

r=rate of interest annually

n=number of compounding per year

t=time in years

Given ; P=$500, A=$750 , r=2.5%=0.025 , t=?,n=1

Substitute values;

A=P(1+r/n)^nt

$750=$500(1+0.025)^t

750=500(1.025)^t

750/500=(1.025)^t

1.5=(1.025)^t

log 1.5 =t log (1.025)

log 1.5/log 1.025 = t

16.4 =t

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Compound interest formula :brainly.com/question/12148233

Keywords : bank account, interest per year, value of account, years

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Y=8x-4 find y and x intercept

dlinn [17]

Answer:

<h3>The x intercept is 1/2</h3><h3>The y intercept is - 4</h3>

Step-by-step explanation:

y = 8x - 4

First to find the y intercept let x = 0

Substitute the value of x into the equation

That's

y = 8(0) - 4

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To find the x intercept let y = 0

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Hope this helps you

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3 years ago

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Answer:

1.6 days (1 3/5 for simplified form).

Step-by-step explanation:

<u>Given equation:</u>

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2 years ago

Solve the Inequality for M:<br> 1 + m/3 < 6

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3 years ago

(-1,2) and (3,4) what's the midpoint ? Show work please.

babymother [125]

The midpoint formula is:
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3 years ago

Using the same data, Complete the following

astra-53 [7]

Answer:

a) $weight = 49.995 +0.103height +\epsilon$

$R^2 = 0.67051225196413$

$R^2_{adj} =0.66160717769289$

$F =75.2955260721013$

b) H0: $\beta_1 =0$

H1: $\beta_1 \neq 0$

On this case the test statistc is given by $t=8.67729946884982$

And the p value obtined was: $p_v =1.88977483236692x10^{-10}$ and since the p value is lower than th significance level we can reject the null hypothesis at 5% of significance. The slope is significant.

$SE_{\beta_1}=0.0118255634597743$

Step-by-step explanation:

We assume the following info:

Gender Height Weight

Male 73.84701702 241.8935632

Male 68.78190405 162.3104725

Male 74.11010539 212.7408556

Male 71.7309784 220.0424703

Male 69.88179586 206.3498006

Male 67.25301569 152.2121558

Male 68.78508125 183.9278886

Male 68.34851551 167.9711105

Male 67.01894966 175.9294404

Male 63.45649398 156.3996764

Male 71.19538228 186.6049256

Male 71.64080512 213.7411695

Male 64.76632913 167.1274611

Male 69.2830701 189.4461814

Male 69.24373223 186.434168

Male 67.6456197 172.1869301

Male 72.41831663 196.0285063

Male 63.97432572 172.8834702

Male 69.6400599 185.9839576

Male 67.93600485 182.426648

Male 67.91505019 174.1159291

Male 69.43943987 197.7314216

Male 66.14913196 149.173566

Male 75.20597361 228.7617806

Male 67.89319634 162.0066518

Male 68.1440328 192.3439766

Male 69.08963143 184.4351744

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And we can use excel to solve the problem

Part a

On this case we need to click on Data>Data analysis>Regression>Ok

We select the input Y range and th X range and then we click in Ok.

The output obtained is on the first figure attached.

And in order to estimate the regression line we need to look into the column Coefficients, and for this case we got:

$\beta_0 =49.995$

$\beta_1 =0.103$

And the linear model would be given by:

$weight = 49.995 +0.103height +\epsilon$

For the determination coefficient we have:

$R^2 = 0.67051225196413$

And the adjusted $R^2 =0.66160717769289$

And if we analyze the output th F statistic is given by:

$F =75.2955260721013$

Part b

We want to test:

H0: $\beta_1 =0$

H1: $\beta_1 \neq 0$

On this case the test statistc is given by $t=8.67729946884982$

The standard error for the slope is given in the output:

$SE_{\beta_1}=0.0118255634597743$

$t=8.67729946884982$

$p_v =1.88977483236692x10^{-10}$

We reject the null hypothesis.

5 0

3 years ago