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pav-90 [236]
3 years ago
11

Select the correct answer. In which prototyping technique, is a solid physical model of a part obtained directly from a 3D CAD d

rawing without the use of tooling? OA virtual prototyping OB. 3D printing O C. rapid prototyping OD. selective laser sintering​
Engineering
1 answer:
Naily [24]3 years ago
6 0
I need a little more to explain
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What is not required for current to flow through a conductor
musickatia [10]

Answer: Something that has air molecules.

Explanation:

5 0
3 years ago
A model of a submarine, 1:15 scale, is to be tested at 180 ft/s in a wind tunnel with standard sea-level air, while theprototype
ella [17]

Answer:

Explanation:

Given

scale i.e. L_r=1:15

Using Reynolds number similarity

(Re)_m=(Re)_p

(\frac{Vl}{\nu })_m=(\frac{Vl}{\nu })_p

Properties of air

\nu _{air}=1.57\times 10^{-4} ft/s

Properties of sea water

\nu _{sea}=1.26\times 10^{-5} ft/s

\left ( \frac{V_ml_M}{\nu _m}\right )=\left ( \frac{V_pl_p}{\nu _p}\right )

V_p=V_m\left ( \frac{l_m}{l_p}\right )\left ( \frac{\nu _p}{\nu _m}\right )

V_p=180\times \frac{1}{15}\times \frac{1.26\times 10^{-5}}{1.57\times 10^{-4}}

V_p=0.963\ ft/s

8 0
3 years ago
Sea A una matriz 3x3 con la propiedad de que la transformada lineal x → Ax mapea R³ sobre R³.
skelet666 [1.2K]

Answer:

ax

Explanation:

7 0
3 years ago
Can anyone answer this question
Solnce55 [7]

Answer:

a) 2.18 m/s^2

b) 9.83 m/s

Explanation:

The flywheel has a moment of inertia

J = m * k^2

Where

J: moment of inertia

k: radius of gyration

In this case:

J = 144 * 0.45^2 = 29.2 kg*m^2

The block is attached through a wire that is wrapped around the wheel. The weight of the block causes a torque.

T = p * r

r is the radius of the wheel.

T = m1 * g * r

T = 18 * 9.81 * 0.6 = 106 N*m

The torque will cause an acceleration on the flywheel:

T = J * γ

γ = T/J

γ = 106/29.2 = 3.63 rad/s^2

SInce the block is attached to the wheel the acceleration of the block is the same as the tangential acceleration at the eddge of the wheel:

at = γ * r

at = 3.63 * 0.6 = 2.81 m/s^2

Now that we know the acceleration of the block we can forget about the flywheel.

The equation for uniformly accelerated movement is:

X(t) = X0 + V0*t + 1/2*a*t^2

We can set a frame of reference that has X0 = 0, V0 = 0 and the X axis points in the direction the block will move. Then:

X(t) = 1/2*a*t^2

Rearranging

t^2 = 2*X(t)/a

t = \sqrt{\frac{2*X(t)}{a}}

t = \sqrt{\frac{2*18}{2.81}} = 3.6 s

It will reach the 1.8 m in 3.6 s.

Now we use the equation for speed under constant acceleration:

V(t) = V0 + a*t

V(3.6) = 2.81 * 3.6 = 9.83 m/s

7 0
4 years ago
Choose the true statement from those shown below: A Merchant Account allows you to use SSL on your web site. Disadvantages of us
Slav-nsk [51]

Answer:

The answer is A. that is, a merchant account allows you to use SSL on your website.

Explanation:

SSL means Secure Sockets Layer and this is an encryption-based Internet security protocol.

For an e-commerce merchant website or account, it is advised that an SSL package be installed to prevent any potential loss of private information.

For this reason, a merchant account allows use of SSL on your website because this also boost the confidence of client and customers visiting the website to purchase products.

7 0
3 years ago
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