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3 years ago

What is the relative % change in P if we double the absolute temperature of an ideal gas keeping mass and volume constant?

Engineering

1 answer:

Contact [7]3 years ago

6 0

Answer: 100% (double)

Explanation:

The question tells us two important things:

Mass remains constant
Volume remains constant

(We can think in a gas enclosed in a closed bottle, which is heated, for instance)

In this case we know that, as always the gas can be considered as ideal, we can apply the general equation for ideal gases, as follows:

State 1 (P1, V1, n1, T1) ⇒ P1*V1 = n1*R*T1
State 2 (P2, V2, n2, T2) ⇒ P2*V2 = n2*R*T2

But we know that V1=V2 and that n1=n2, som dividing both sides, we get:

P1/P2 = T1/T2, i.e, if T2=2 T1, in order to keep both sides equal, we need that P2= 2 P1.

This result is just reasonable, because as temperature measures the kinetic energy of the gas molecules, if temperature increases, the kinetic energy will also increase, and consequently, the frequency of collisions of the molecules (which is the pressure) will also increase in the same proportion.

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What impact does modulus elasticity have on the structural behavior of a mechanical design?

devlian [24]

Answer with Explanation:

The modulus of elasticity has an profound effect on the mechanical design of any machine part as explained below:

1) Effect on the stiffness of the member: The ability of any member of a machine to resist any force depends on the stiffness of the member. For a member with large modulus of elasticity the stiffness is more and hence in cases when the member has to resist a direct load the member with more modulus of elasticity resists the force better.

2)Effect on the deflection of the member: The deflection caused by a force in a member is inversely proportional to the modulus of elasticity of the member thus in machine parts in which we need to resist the deflections caused by the load we can use materials with greater modulus of elasticity.

3) Effect to resistance of shear and torque: Modulus of rigidity of a material is found to be larger if the modulus of elasticity of the material is more hence for a material with larger modulus of elasticity the resistance it offer's to shear forces and the torques is more.

While designing a machine element since the above factors are important to consider thus we conclude that modulus of elasticity has a profound impact on machine design.

8 0

3 years ago

"Using your favorite search engine and the resources of your library, develop a set of recommendations regarding the possible us

alina1380 [7]

Answer:

Cloud computing services are going to be very important to supporting Ashville's mobile app since it has different uses. These applications uses include; data storage, as well as helping to provide network to any business data related work. This will improve the city of Ashville's mobile app operations considerably.

The benefits of using cloud computing are; it allows a business managers to be more concerned with running the business themselves rather than maintaining the data center. The use of cloud computing allows a company's IT administrators to focus on managing the company's operations, thereby allowing performance to be enhanced of the business enterprise.

A commercial company is able to create new technologies more rapidly with the use of cloud computing. Furthermore, the enterprise will be able to automate its activities using cloud computing. Cloud computing is also very important as it is more affordable and thus promotes the company's growth in the market. Cloud computing is also enhancing the global presence of the Ashville mobile app. The drawbacks of using cloud computing include the following; due to using the cloud infrastructure, the company's performance may be unreliable. People believe that cloud computing is not reliable and that cloud computing may not be secure at last and can't always be right for all workloads.

Explanation:

5 0

3 years ago

Which two pieces of evidence best support the statement: “Germs do not always cause disease”?

Ratling [72]

Answer:

1) "Most germs are too small to cause disease" http://ecufrog.weebly.com/uploads/8/6/7/7/8677638/850_meet_the_microbes.pdf

2) "Some bacteria that live in your body are helpful. For instance, Lactobacillus acidophilus... helps you digest food, destroys some disease-causing organisms and provides nutrients." https://www.mayoclinic.org/diseases-conditions/infectious-diseases/in-depth/germs/art-20045289

8 0

3 years ago

A westbound section of freeway currently has three 12-ft wide lanes, a 6-ft right shoulder, and no ramps within 3 miles upstream

Tresset [83]

Answer:

•Estimated density = 39.685Pc/mi/en

•Level of service, LOS frequency = LOSC

Explanation:

We are given:

•Freeway current lane width,B = 12ft

• freeway current shoulder width,b = 6ft

• percentage of heavy vehicle, Ptb = 10℅

• peak hour factor, PHF = 0.9

Let's consider,

•Number of lanes N = 4

• flow of traffic V = 7500vph

• percentage of Rv = 0, therefore the freeflow speed in freeway FFS = 70mph

• cars equivalent for recreational purpose Er= 2

•cars to be used for trucks and busses Etb= 2.5

Let's first calculate for the heavy adjustment factor.

We have:

$F_H_v = \frac{1}{1+P_t_b(E_t_b-1)+Pr(Er-1)}$

Substituting figures in the equation we have:

$= \frac{1}{1+0.1(2.5-1)+0(2-1)}$

= 0.75

Let's now calculate equivalent flow rate of the car using:

$Vp = \frac{V}{(P_H_F)*N)*(F_H_v)*(F_p)}$

$= \frac{7500}{0.9*4*0.75*1}$

= 2777.7 pc/h/en

Calculating for traffic density, we have:

$D = \frac{Vp}{FFS}$

$D = \frac{2777.7}{70}$

D = 39.685 Pc/mi/en

Using the table for LOS criteria of basic frequency segment, the level of service LOS of frequency is LOSC

4 0

3 years ago

Consider the following fragment of code in an authentication program:

Juli2301 [7.4K]

Answer:

Backdoor

Explanation:

The back door fragment in a program allows user to access backdoor information without necessarily following the common security procedures needed. In this case, once the programmer keys in the username he or she logs in without putting password. Therefore, this is a backdoor fragment.

8 0

3 years ago