Answer:

Explanation:
Given that
Calorific value (CV) = 44 MJ/Kg
CV= 44,000 KJ/kg
Brake thermal efficiency(η) = 37.9 %
We know that

Where BP is the brake power



Brake specific fuel consumption (s)




Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.