Answer:
6x+21
Step-by-step explanation:
The coordinate of the vertex is; (h, k) = (3, -5)
The final equation of the parabola is; y = 5(x - 3)² - 5
<h3>How to find the vertex of a Parabola?</h3>
The vertex is the coordinate of the crest or trough of the curve. Now, in the given graph, we only have a Trough which is the lowest point of the graph.
The coordinate of the vertex is; (h, k) = (3, -5)
2) Since the general equation is;
y = a(x - h)² + k
We will have;
y = a(x - 3)² - 5
At x = 2, y = 0. Thus;
0 = a(2 - 3)² - 5
a - 5 = 0
a = 5
3) The final equation of the parabola is;
y = 5(x - 3)² - 5
Read more about Parabola Vertex at; brainly.com/question/17987697
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Answer:
That sucks.
Step-by-step explanation:
Answer:
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
Step-by-step explanation:
Given:
Let,
point S( x₁ , y₁) ≡ ( -1 , 1)
point T( x₂ , y₂) ≡ (3 , -5)
Point M( x , y ) is the Mid point of segment ST.
To Find:
Point M( x , y )= ?
Solution:
As Point M( x , y ) is the Mid point of segment ST.
So we have Mid Point Formula as
On substituting the given values in above equation we get
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
