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The vertex of f(x) = 3x^2 + 12x − 8 is (2,28) absolute minimum
<h3>How to determine the vertex?</h3>
The equation is given as:
f(x) = 3x^2 + 12x − 8
Differentiate the function
f'(x) = 6x + 12
Set to 0
6x + 12 = 0
Divide through by 6
x + 2 = 0
Solve for x
x = -2
Substitute x = -2 in f(x) = 3x^2 + 12x − 8
f(2) = 3 *2^2 + 12 *2 − 8
Evaluate
f(2) = 28
This means that the vertex is (2,28)
A quadratic function is represented as:
f(x) =ax^2 + bx + c
When a is positive, then the vertex of the function is an absolute minimum.
This means that f(x) = 3x^2 + 12x − 8 has an absolute minimum vertex because 3 is positive
Read more about quadratic functions at:
brainly.com/question/18797214
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Answer: 15 10
Step-by-step explanation:
B. attend fewer movies.
He should put more time into cutting grass but that's not an option. He doesn't have any more to put into savings and he's already over budget for his movies/music purchases. The only logical solution would be B.
