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Pavel [41]
2 years ago
9

5. When would it be necessary for the two daughter cells to be different than the mother cel

Biology
1 answer:
dexar [7]2 years ago
6 0

Answer:

Living cells go through a series of stages known as the cell cycle. The cells grow, copy their chromosomes, and then divide to form new cells.

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Carbon dioxide in the atmosphere traps heat. Scientists are concerned that too much carbon dioxide is being released into the ai
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Which of the following best defines change in a species over time?
Firlakuza [10]

Answer:

Evolution

Explanation:

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On May 18, 1980, Mount St. Helens in Washington State experienced a huge volcanic eruption after a magnitude 5.1 earthquake. Dur
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<h2>Correct answer is option "a"</h2>

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9 0
3 years ago
Read 2 more answers
A certain buffer is made by mixing a weak acid HA and its conjugate base A–. When HA is present at a concentration of 0.5 mM and
MAVERICK [17]

Answer:The ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

Explanation:

The dissociation constant for formic acid = K_a=1.8\times 10^{-4}

Concentration of HA= 0.5 mM

Concentration of A^-= 0.1 mM

pH = 6.16

First we have to calculate the value of K_a.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[A^-}{[HA]}

Now put all the given values in this expression, we get:

6.16=pK_a+\log (\frac{[0.1]}{0.5})

pK_a=6.86

To calculate the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02.

Using Henderson Hesselbach equation :

7.02=6.86+\log \frac{[A^-]}{[HA]}

7.02=6.86+\log \frac{[A^-]}{[HA]}

\frac{[A^-]}{[HA]}=1.44

\frac{[HA]}{[A^-]}=0.69

Thus the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

7 0
3 years ago
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