Some living thing's bodies are weaker than others. For the species to live, the strong ones of the species will not get sick, reproduce and create strong offspring. The weak will die out.
Mitochondria are made from the process called binary fission. This is the cell division utilized by the prokaryotes. It also has circular DNA that is similar in both size and structure in prokaryotic cells. Mitochondria also has its own DNA different than the DNA found in the nucleus of a cell.
Answer:
3 long tails : 1 short tail
Explanation:
This question involves a single gene coding for tail length in mice. The allele for long tail (T) is dominant over the allele for short tail (t). This means that an heterozygous mice will possess the long tail length.
According to this question, in a cross between two hybrid or heterozygote mice i.e. Tt × Tt, the following gametes will be produced by each parent:
Tt - T and t
Using these gametes in a punnet square (see attached image), the following will be produced: TT, Tt, Tt and tt.
Offsprings with genotype TT, Tt and Tt will have a LONG TAIL while genotype tt will have a SHORT TAIL. Hence, the phenotypic ratio will be 3 long tails : 1 short tail.
Describe the behavior of brown bats
Answer:
linkage with approximately 33 map units between the two gene loci
Explanation:
If two genes are not linked, number of recombinants and parental offspring will be equal. Here it is clearly visible that recombinants are less than parental offspring hence the genes are linked. Given, the offspring are in following numbers:
AaBb = 106 = Parental
aabb = 94 = Parental
Aabb = 48 = Recombinant
aaBb = 52 = Recombinant
Recombination frequency = (Number of recombinants/ Total progeny) * 100 = (100/300) * 100 = 33.33 %
1% recombination frequency= 1 map unit of distance between the two gene loci. So here the distance between the two gene loci is approximately 33 map units.
Hence, these results are consistent with linkage with approximately 33 map units between the two gene loci
