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3 years ago

Is (1, 10) a solution to this system of equations?

Mathematics

1 answer:

Mama L [17]3 years ago

5 0

(1,10) satisfy the first equation and the second equation.

Since the x-coordinate is 1 and the y-coordinate is 10, you can plug these numbers in for the x and y of the equation like this:

10 = 1 + 9

10 = 10

This satisfy the first equation of y = x + 9

10 = 9(1) + 1

10 = 10

This satisfy both of the equations, so this is a solution to this system of equations.

LOL! I was in eighth grade last year, I understand the struggle! ._.

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Amy's yearly salary is given by the equation y = 25,000 + 700x, where x is the number of years since 2007 and y is her salary in

yanalaym [24]

2007 would be 0 years since 2007

y=25000+700(0)
y=25000

Answer: Her yearly salary in 2007 was $25,000

Hope this helps:)

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4 years ago

Ohms Law states that in and electrical circuit E=IR, where E represents the pontial (in volts). I represents the current (in amp

gogolik [260]

Answer:

40 A

Step-by-step explanation:

E=I.R ==> I=E/R

if E=6 and R=0.15 then:

I= (6/0.15)= 40 A

7 0

3 years ago

Read 2 more answers

Tim spent half of his my allowance going to the movies. He washed the family car and earned 6 dollars. What was his weekly allow

puteri [66]

17 - 6 = 11
11 * 2 = 22
22 + 6 = 28
Weekly allowance = $28

4 0

3 years ago

Can someone please help me out with this its really urgent Ill mark brainliest

Alex73 [517]

Answer:

smart dot company c=.50t+12

communication plus c=2.50t

Step-by-step explanation:

smart dot has the starting point of $12 per month already so that would be your y-intercept with the equation being y=mx+b , y being the cost m being the amount of money per hour, x being the time spent, and b being the starting cost.

So with that smart dot would be c=.50t+12

with communication plus not having that starting point it would just be c=2.50t

7 0

3 years ago

What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300

hodyreva [135]

Answer:

Option B.

Step-by-step explanation:

Let as consider the given equation:

$2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30$

It can be written as

$2(\ln 2x)-(\ln 10x)=\ln 30$ $[\because \ln e^a=a]$

$\ln (2x)^2-(\ln 10x)=\ln 30$ $[\because \ln a^b=b\ln a]$

$\ln \dfrac{4x^2}{10x}=\ln 30$ $[\because \ln \dfrac{a}{b}=\ln a-\ln b]$

$\ln \dfrac{2x}{5}=\ln 30$

On comparing both sides, we get

$\dfrac{2x}{5}=30$

Multiply both sides by 5.

$2x=150$

Divide both sides by 2.

$x=75$

Therefore, the correct option is B.

7 0

3 years ago