Pytagorean theorem
height10
attached at 10-4=6 yards from bottom
8 yards from base to away
a^2+b^2=c^2
a and b are side legnths and c=hypotonuse
so therfore we are given a and b and we must solve for c
so
6=height
8=base
6^2+8^2=c^2
36+64=c^2
100=c^2
square root
10=c
so therfor the legnth of each cable is 10 yards
3 cables so 3 times 10=30
30 yards needed
We have
![3y+8-7y=11](https://tex.z-dn.net/?f=3y%2B8-7y%3D11)
First, we can combine like terms 3y and -7y to get -4y.
Then, we have
![-4y+8=11](https://tex.z-dn.net/?f=-4y%2B8%3D11)
We could then subtract 8 on both sides to get
![-4y=3](https://tex.z-dn.net/?f=-4y%3D3)
Finally, we isolate y completely by dividing both sides by -4, to get
Answer:
The selling price after the markup is $1.82
Step-by-step explanation:
$1.40 * .30 =
Multiply $1.40 times .30 (which is same as 30%)
$1.40 * .30 = $0.42
Add $1.40 and $0.42
= $1.82
Hope this helps.
It’s 8. 4 can go into 8, two times
A and B are equal to 27^-1