Answer:
Therefore the one combination is
200 tickets of Children and 100 tickets of Adult.
Therefore Total Amount will be given as
..........As Required
Step-by-step explanation:
Given:
Children's tickets cost = 5$ (per ticket)
Adult tickets cost = 10$ (per ticket)
Total Amount = 2000$
Let the number of Children's Ticket be " x "
and the number of Adult's Ticket be " y "
Therefore,
Total cost for Children's Ticket will be = ![5\times x](https://tex.z-dn.net/?f=5%5Ctimes%20x)
Total cost for Adult's Ticket will be = ![10\times y](https://tex.z-dn.net/?f=10%5Ctimes%20y)
Therefore Total Amount will be given as
...........As Required
So there are many combinations to get 2000$ one of the as follow
Children's tickets cost = 1000$
∴ ![5x = 1000\\x=\dfrac{1000}{5}=200\ tickets](https://tex.z-dn.net/?f=5x%20%3D%201000%5C%5Cx%3D%5Cdfrac%7B1000%7D%7B5%7D%3D200%5C%20tickets)
Adult's tickets cost = 1000$
![10x = 1000\\x=\dfrac{1000}{10}=100\ tickets](https://tex.z-dn.net/?f=10x%20%3D%201000%5C%5Cx%3D%5Cdfrac%7B1000%7D%7B10%7D%3D100%5C%20tickets)
Therefore the one combination is
200 tickets of Children and 100 tickets of Adult.