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Tems11 [23]
3 years ago
11

Kendra needs 1/3 cup of nuts for a cake she is making it she had 8 cups of nuts how many cakes could she make ​

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

24 cakes

Step-by-step explanation:

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Sean's house is currently worth $188,900. According to a realtor, house prices in Sean's neighborhood will increase by 4.8% ever
mrs_skeptik [129]

Answer  

Given

Sean's house is currently worth $188,900.

According to a realtor, house prices in Sean's neighborhood will increase by 4.8% every year.

To prove

Formula

Compound\quaterly\ interest = Principle (1 + \frac{r}{4})^{4t}

Where r is the rate in the decimal form.

As given

Take\ Principle\ = P_{0}

Rate = \frac{4.8}{100}

              = 0.048

Put in the formula

Compound\quaterly\ interest = P_{0}(1 + \frac{0.048}{4})^{4t}

Compound\quaterly\ interest = P_{0} (1 + \frac{0.048}{4})^{4t}

Compound\quaterly\ interest = P_{0} (1 + 0.012)^{4t}       Compound\quaterly\ interest = P_{0} (1.012)^{4t}  

Now also calculated monthly.

Formula

Compound\ monthly = Principle (1 + \frac{r}{12})^{12t}

As given

Take\ Principle\ = P_{0}

Rate = \frac{4.8}{100}

              = 0.048

Put in the formula

Compound\ monthly = P_{0} (1 + \frac{0.048}{12})^{12t}

Compound\ monthly = P_{0} (1 + 0.004)^{12t}

Compound\ monthly = P_{0} (1.004)^{12t}

As the approximation quarterly growth rate of the value of sean's house is near the Compounded quarterly interest .

Thus Option (A) is correct.

i.e

The expression (1.0118)^{4t} reveals the approximate quarterly growth rate of the value of Sean's house.




                                               

                                                       




6 0
4 years ago
Read 2 more answers
A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2​, drawn from the 11​, will
svet-max [94.6K]

The required probability is \frac{36}{55}

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.  

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, \text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}

Probability for first draw to be non-defective =\frac{11-2}{11}=\frac{9}{11}

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective =\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}

(printers after first slot = 10; total defective printers = 2)

Then, total probability =\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}

7 0
4 years ago
Is 4-heap Nim with heaps of sizes 22, 19, 14, and 11 balanced or unbalanced? Player I's first move is to remove 6 coins from the
nadya68 [22]

Answer:

Player II should remove 14 coins from the heap of size 22.

Step-by-step explanation:

To properly answer this this question, we need to understand the principle and what it is exactly is being asked.

This question revolves round a game of Nim

What is a game of Nim: This is a strategic mathematical game whereby,  two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.

Now, referring back to the question, we should first understand that:

                        22₂ = 1 0 1 1 0

                         19₂= 1 0 0 1 1

                         14₂= 0 1 1 1 0

                          11₂= 0 1 0 1 1

and also that the “bit sums” are all even, so this is a balanced game.

However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.

3 0
4 years ago
Find the length of segment AB if A (4, 1) and B(1,3). Round to the nearest hundredth, if needed.
viktelen [127]

Answer:

\sqrt{13}

Step-by-step explanation:

A(4;1) B(1;3)

●use distance formula (see photo^)

8 0
3 years ago
How many and what type of solutions does the equation have?
ella [17]

Answer: C

Step-by-step explanation:

Simplify to 4x^2 + 12x + 5 = 0 so that all the terms are on one side.

Do a part of the quadratic formula to see.

You only need to do the -b^2-4ac part. If it is negative, that means there are irrational solutions. If it is positive, it has two solutions. If it is 0, it has 1 solution.

12^2-4(4)(5) = 64

It is positive so it has two solutions.

7 0
3 years ago
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