Answer:
V0 = 48 feet per second is the answer.
Step-by-step explanation:
The given function which represents height of a golf ball in feet after x seconds after a player hits it.
y = -16x² + v0x
here v0 is the initial velocity and we have to calculate initial velocity. The ball returns to the ground 3 seconds after it is hit.
After 3 seconds height of the ball will be 0.
Now from the given function
0 = -16(3)² + v0×3
3v = 16×9
v0 = 16×9/3 = 48 feet per second.
Answer:
Step-by-step explanation:
F = ma
ma = F
a = F/m
Step-by-step explanation:
.....because the coefficient of x is 2, a positive number.
48 because that's what you get following your equation in PEMDAS order :)
Answer:
6xy²z^4
Step-by-step explanation:
![\sqrt[3]{216x^3y^6z^12}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E3y%5E6z%5E12%7D)
= ∛(6³)(x³)(y³)(y³)(z³)(z³)(z³)(z³) = 6x·y·y·z·z·z·z = 6xy²z^4
