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Bas_tet [7]
3 years ago
8

Pythagorean theorem (picture provided)

Mathematics
2 answers:
e-lub [12.9K]3 years ago
8 0

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

Ilya [14]3 years ago
7 0
The answer is definitely D:)
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WILL GIVE BRAINLIEST
Rasek [7]

the distance between the 2 points is 10

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2 years ago
For his exercise today, Manuel plans to both run and swim. Let r be the number of laps he runs and lets be the number of laps he
QveST [7]

Answer:

The Inequality describing the situation is 3r+2s>45.

Step-by-step explanation:

Let the number of laps he runs be 'r'

Let the number of laps he swims be 's'

Now Given:

Time required to run each lap = 3 min

Time required to swim each lap = 2 min

Total minutes he need to exercise more than 45

we need to write the Inequality representing the same.

Solution:

Now we can say that;

Time required to run each lap multiplied by the number of laps he runs plus Time required to swim each lap multiplied by the number of laps he swims should be greater than Total minutes he need to exercise.

framing in equation form we get;

3r+2s>45

Hence The Inequality describing the situation is 3r+2s>45.

6 0
2 years ago
Please help, doing age word problems. Tysm if you do, really appreciated :D
topjm [15]

Answer:

D (12, 21); B (11, 17); C (18,28); D (42); C (8).

Step-by-step explanation:

First:

Let I represent Isabel and M represent Marie.

We know that currently, Isabel is 9 years older than Marie, or:

I=9+M.

In three years, Isabel will be six years less than twice of Marie's age. In other words:

(I+3)= 2(M+3)-6

Now solve. Substitute I.

(9+M+3)=2M+6-6

12+M=2M

M=12; I=21. Marie is 12 while Isabel is 21.

Second:

Let I represent Isabel and M represent Marie.

Isabel is 6 years older than Marie; in other words: I=6+M

In 4 years, Isabel will be 9 years less than twice Marie's age. Or:

(I+4)=2(M+4)-9

Solve. Substitute I.

(6+M+4)=2(M+4)-9

10+M=2M+8-9

10+M=2M-1

11=M; I=17; Marie is 11 while Isabel is 17.

Third:

Let I represent Isabel and M represent Marie.

Isabel is 10 years older than Marie, or: I=10+M

In 2 years, twice Isabel's age is three times Marie's age. Or:

2(I+2)=3(M+2)

Solve. Substitute for I.

2(10+M+2)=3(M+2)

24+2M=3M+6

18=M; I=28. Marie is 18 while Isabel is 28.

Fourth:

Let M represent Mary and A represent Ann.

Mary is 3 time as old as Ann. Or: M=3A

7 years ago Mary was 5 times as old as Ann. In other words:

(M-7)=5(A-7)

Solve for this system. Substitute M.

(3A-7)=5A-35

-2A=-28

A=14; M=42; Mary is 42.

Fifth:

Let T represent Tammy and L represent Laurel.

We know that Tammy is 42 while Laurel is 9. In other words:

T=42 and L=9.

We need to find in how many years will 3 times Laurel's age be 1 more than Tammy's age. In other words, let's let y represent the amount of years. Thus:

3(L+y)=(T+y)+1

We already know L and T:

3(9+y)=(42+y)+1

27+3y=43+y

2y=16

y=8

In 8 years, when Laurel is 17 and Tammy is 50. (3 times 17 is 51, one more than 50).

5 0
3 years ago
Read 2 more answers
HELPPPP PLEASE!!!! Don't understand
iragen [17]

Answer: 20% is your answer


Step-by-step explanation:

180-150=30

30 divided by 150 = .2 which is 20%

7 0
3 years ago
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Aline's y-intercept is -6 and its slope is 0.What is its equation in slope-intercept form?
notka56 [123]

Answer:

y=0x+-6

Step-by-step explanation:

y=mx+b

6 0
3 years ago
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