Answer:
no equation given ,pls mention it in the comments
Using the concept of domain, the domain of (f.g)(x) is given by:
{x ∈ ℝ | x ≠ 3}
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- The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
- In the graph, <u>function f assumes all real values.</u>
- Function g is not defined for x = 3, thus, it's domain is all real values except 3.
- Thus, the multiplication, as
, will also not be defined at x = 3, and the domain of the multiplication is:
{x ∈ ℝ | x ≠ 3}
A similar problem is given at brainly.com/question/4175434
Give a reason for each step of the proof.
Given: <1 and <2 are complimentary
<1 is congruent to <3,
<2 is congruent to <4
Prove: <3 and <4 are complimentary
Statements: Reasons:
1. <1 and <2 are complimentary 1.Given
2. m<1 + m<2=90* 2.<u>DEFINITION OF COMPLEMENTARY ANGLES</u>
3. <1 is congruent to <3, <2 is congruent to <4 3.__GIVEN______
4. m<1=m<3, m<2=m<4 4.<u>DEFINITION OF CONGRUENT ANGLES_</u>
5. m<3 + m<2=90* 5. <u>SUBSTITUTION PROPERTY (m<1 is replaced by m<3.) </u>
6. m<3 +m<4=90* 6. <u>DEFINITION OF COMPLEMENTARY ANGLES </u>
7. <3 and <4 are complimentary 7.<u> DEFINITION OF COMPLEMENTARY ANGLES</u>
X-y=3=>x=3+y
X+2y=-6
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3+y+2y=-6
3+3y=-6
3y=-6-3
3y=-9
y=-3
X+2y=-6
X+2(-3)=-6
X-6=-6
X=0
Step-by-step explanation:
tricky, as the sequence does not define the input values.
by we can assume that the corresponding input values are 1, 2, 3, 4, 5, ... as it is usual for a sequence.
in that sense, b is the correct answer.
