What does it mean when a function is one-to-one?

1 answer:

3 0

Let a function be defined from A to B then f is said to be one to one function if every element of domain has its unique image in co- domain . In other words, if each separate elements of set A are mapped with separate of set B then such function is known as one to one function.

You might be interested in

Which statement best explains why the graphed relation is not a function?

shusha [124]

Answer:

Step-by-step explanation:

Because you can't have multiple x-values. You can only have multiple y-values.

4 0

2 years ago

Need help with questions <br> 2. and 3.

emmainna [20.7K]

9514 1404 393

Answer:

2) x = 7

3) x = 5

Step-by-step explanation:

When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.

2) All of the angles are right angles.

11x +13 = 90

11x = 77 . . . . . . subtract 13

x = 7 . . . . . . . divide by 11

3) The two marked angles are acute.

16x = 80 . . . . the acute angles are congruent

x = 5 . . . . . . divide by 16

5 0

2 years ago

Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$