NEED HELP AS FAST AS POSSILBLE

Mathematics

1 answer:

erica [24]3 years ago

8 0

You know height = 500 feet

You know time = 6 hours

Feet per hour = feet/hour

Descending = going down

Solution: -500/6

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PLEASEE HELPP WILL BRAINLIST why would the average rate of the change be equal to zero from x = -2 to x = 6?

sweet-ann [11.9K]

Answer:

x=5

Step-by-step explanation:

I was working on this problem also.

Maybe my version will help, too.

You need to sketch f given the information you have.

f'(x) is approximately a a cubic polynomial which means f will look like a quartic (think W)

f slopes down (negative slope) to x=2 and then slopes down again...this is a horizontal tangent.

f then slopes down to to x=5 where is has a minimum and then slopes up.

if im not wrong

7 0

2 years ago

Simplify.

bixtya [17]

Answer:

$\frac{3+i}{-2i}$ = -0.5 + 1.5i

Step-by-step explanation:

Given 3+i divided by -2i ⇒ $\frac{3+i}{-2i}$

By multiplying the numerator and the denominator by the conjugate of (-2i) which will be equal (2i)

So, $\frac{3+i}{-2i}$ = $\frac{3+i}{-2i} *\frac{2i}{2i} = \frac{i(3+i)}{-2i^2} = \frac{i^2+3i}{-2i^2}$

We should know that: i = √(-1) ⇒ i² = -1

∴ $\frac{i^2+3i}{-2i^2} = \frac{-1+3i}{-2*-1} = \frac{-1+3i}{2} = -0.5 + 1.5i$

∴ $\frac{3+i}{-2i}$ = -0.5 + 1.5i

5 0

3 years ago

Please help with this problem. I keep getting -25

katrin [286]

$\bf -\sqrt[5]{-(400^2)}\implies -\sqrt[5]{-[(20\cdot 20)^2]}\implies -\sqrt[5]{-[(20^2)^2]}
\\\\\\
-\sqrt[5]{-(20^{2\cdot 2})}\implies -\sqrt[5]{-(20)^4}\implies -\sqrt[5]{-(2^2\cdot 5)^4}
\\\\\\
-\sqrt[5]{-2^{2\cdot 4}\cdot 5^4}\implies -\sqrt[5]{-2^8\cdot 5^4}\implies -\sqrt[5]{-2^{5+3}\cdot 5^4}
\\\\\\
-\sqrt[5]{-2^5\cdot 2^3\cdot 5^4}\implies 2\sqrt[5]{2^3\cdot 5^4}\implies 2\sqrt[5]{5000}$