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s2008m [1.1K]
4 years ago
10

You work as a lab assistant. Each morning you are responsible for grouping the correct number of test tubes for

Mathematics
1 answer:
aksik [14]4 years ago
8 0

Answer:

<h2>Option D is correct.</h2>

Step-by-step explanation:

In total 40 test tubes are required for 12 experiments.

The first two experiments will require 4 test tubes for each.

Hence, there will be a requirement of 4\times2 = 8 test tubes.

Six experiments require 3 test tubes each.

Hence, these 6 experiments will take 6\times 3= 18 test tubes.

Other 2 experiments will take 2 test tubes.

Here, 2\times2 = 4 test tubes will be required.

Till now a total of (8 + 18 + 4) = 30 test tubes have been used.

The remaining number of test tubes is (40 - 30) = 10.

The remaining experiments require \frac{10}{2} = 5 test tubes.

The first calculation to perform is 2(4) + 6(3) - 2(2).

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Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

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