Please reply only in CORAL. I am not sure how to get the numbers between the negative version and positive version of the input

Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r

kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

INVOKE Str_find,ADDR target, ADDR source

mov position,eax

jz wasfound ; ZF=1 indicates string found

mov edx,OFFSET str3 ; string not found

call WriteString

jmp quit

wasfound: ; display message

mov edx,OFFSET str1

call WriteString

mov eax,position ; write position value

call WriteDec

mov edx,OFFSET str2

call WriteString

quit:

exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

; to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

INVOKE Str_length,pTarget ; get length of target

mov lenTarget,eax

INVOKE Str_length,pSource ; get length of source

mov lenSource,eax

mov edi,OFFSET target ; point to target

mov esi,OFFSET source ; point to source

; Compute place in target to stop search

mov eax,edi ; stop = (offset target)

add eax,lenTarget ; + (length of target)

sub eax,lenSource ; - (length of source)

inc eax ; + 1

mov stop,eax ; save the stopping position

; Compare source string to current target

cld

mov ecx,lenSource ; length of source string

L1:

pushad

repe cmpsb ; compare all bytes

popad

je found ; if found, exit now

inc edi ; move to next target position

cmp edi,stop ; has EDI reached stop position?

jae notfound ; yes: exit

jmp L1 ; not: continue loop

notfound: ; string not found

or eax,1 ; ZF=0 indicates failure

jmp done

found: ; string found

mov eax,edi ; compute position in target of find

sub eax,pTarget

cmp eax,eax ; ZF=1 indicates success

done:

ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0

3 years ago

write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average

bekas [8.4K]

Answer:

#include <stdio.h>

int MaxMark(int* arr, int size) {

int maxMark = 0;

if (size > 0) {

maxMark = arr[0];

}

for (int i = 0; i < size; i++) {

if (arr[i] > maxMark) {

maxMark = arr[i];

}

return maxMark;

}

int SumMarks(int* arr, int size) {

int sum = 0;

for (int i = 0; i < size; i++) {

sum += arr[i];

}

return sum;

}

float AvgMark(int* arr, int size) {

int sum = SumMarks(arr, size);

return (float)sum / size;

}

int main()

{

int student0[] = { 7, 5, 6, 9 };

int student1[] = { 3, 7, 7 };

int student2[] = { 2, 8, 6, 1, 6 };

int* marks[] = { student0, student1, student2 };

int nrMarks[] = { 4, 3, 5 };

int nrStudents = sizeof(marks) / sizeof(marks[0]);

for (int student = 0; student < nrStudents; student++) {

printf("Student %d: max=%d, sum=%d, avg=%.1f\n",

student,

MaxMark(marks[student], nrMarks[student]),

SumMarks(marks[student], nrMarks[student]),

AvgMark(marks[student], nrMarks[student]));

}

return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0

2 years ago

Lindsay owns a candy store that typically makes all of its sales to tourists visiting a nearby zoo. Why might she decide to set

umka2103 [35]

Social media is so powerful in this generation because it is able to reach many different corners of the world. It is not only used merely for communication but also sometimes or most of the times for business. For Lindsay, the use of social media will allow her to increase the size of the customer base. The answer is letter A.

4 0

3 years ago

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Proxy is a network computer that can serve as an intermediary for connecting with other computers.

Keith_Richards [23]

Answer:Protects the local network from outside access

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3 years ago

What is the best way to use a prototype to better understand yolir audience?

9966 [12]

I would say A. Test it and receive feedback

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2 years ago