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ankoles [38]
3 years ago
12

Write three fractions equivalent to 27/30. show work

Mathematics
1 answer:
Kipish [7]3 years ago
4 0
54/60 108/120 216/240 double both numbers each time
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What is 2.1 as a fraction?
german
2 1/10 because the 1 in 2.1 is in the tenth place
7 0
3 years ago
Solving the whole thing
erik [133]
Let
x---------------> distance from people living to the city center

we Know that
Zone 1 covers people living within three miles of the city center
Zone 1 ------------> [x < 3 miles]

Zone 2 covers those between three and seven miles from the center
Zone 2 ------------> [ 3 <= x < = 7  miles]

Zone 3 covers those over seven miles from the center
Zone 3 ------------> [  x > 7  miles]

<span>calculate the distance between two points to find the value of x
</span>
case A) point (0,0)  point (3,4)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(4-0)² +(3-0)²]------> √[16+9]
x=√25-------------> x=5 miles

the answer Part A)
people living in (3,4)
x=5 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]


case B) point (0,0)  point (6,5)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(5-0)² +(6-0)²]------> √[25+36]
x=√61-------------> x=7.81 miles

the answer Part B)
people living in (6,5) 
x=7.81 miles -------------> covers Zone 3 [  x > 7  miles]

case C) point (0,0)  point (1,2)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(2-0)² +(1-0)²]------> √[4+1]
x=√5-------------> x=2.23 miles

the answer Part C)
people living in (1,2) 
x=2.23 miles -------------> covers Zone 1 [ x < 3  miles]

case D) point (0,0)  point (0,3)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(3-0)² +(0-0)²]------> √[9]
x=√9-------------> x=3 miles

the answer Part D)
people living in (0,3) 
x=3 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]

case E) point (0,0)  point (1,6)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(6-0)² +(1-0)²]------> √[36+1]
x=√37-------------> x=6.08 miles

the answer Part E)
people living in (1,6) 
x=6.08 miles -------------> covers Zone 2 [ 3 < = x <= 7  miles]

4 0
3 years ago
Solve each equation for y<br><br> 2x+y=5<br><br> 2x-y+=5<br><br> x+2y=5
frosja888 [35]

Answer:

1. y=5-2x

2. -y=5-2x

3. \frac{5 - x}{2}

Step-by-step explanation:

1. 2x+y=5

y=5-2x

2. 2x-y=5

-y=5-2x

3. x+2y=5

2y=5-x

\frac{5 - x}{2}

<h2>please mark me brainliest</h2>
4 0
2 years ago
Find the values of x and y. Show your work pls (7x-4) (4y+8) 24 and 31
abruzzese [7]

Answer:

The value of x is 5.

The value of y is 4.

Step-by-step explanation:

From the figure, the lengths of the lines with equal number of markings are equal.

So, we will have the length of 7x - 4 = 31.

We solve for 'x'.

We get: 7x = 35

⇒ x = 5

Similarly, 4y + 8 = 24

⇒ 4y = 24 - 8

⇒ 4y = 16

⇒ y = 4

Therefore, the value of x = 5 and y = 4.

Hence, the answer.

8 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
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