Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
Answer:
Answer
5.0/5
23
Let's find the unit rate stemming from $18 for 4 games:
$18
------------- = $4.50/game
4 games
Let's do the same for $27 for 6 games:
$27
------- = $4.50/game (same as before)
6 g
Thus, the const. of prop. is $4.50/game, and the cost function is
C(x) = ($4.50/game)x, where x is the # of games played.
Answer:
Hope it helps....!!!!!
Step-by-step explanation:
AB = c = 38
BC = a = 29
AC = b
Angle ABC = 63 degrees
Solving for AC "b":
Cosine rule: c^2 = a^2 * b^2 -2ab * cos C
38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)
1444 = 841 * b^2 - 58 * b * 0.955
(1444 + 58)/0.955 = b^2 * b
1572.77486911 = b^3
11.62935 = b
11.63 = b (rounded to two decimal places)
Now solving for angle A:
Sine rule: a/sinA = b/sinB
29/sinA = 11.63/sin(63)
sinA/29 = sin(63)/11.63
sin A = (sin(63)/11.63) * 29
sin A = 0.41731
A = sin^-1 (0.41731)
A = 24 degrees 39 minutes 53 seconds
Now solving for angle C:
Sine rule: c/sinC = b/sinB
38/sinC = 11.63/sin(63)
sinC/38 = sin(63)/11.63
sin C = (sin(63)/11.63) * 38
sin C = 0.54682
C = sin^-1 (0.54682)
C = 33 degrees 8 minutes 56 seconds
let's suppose x is the shortest leg of the triangle
The perimeter of the flower bed is 3x+8 ft
the surface to be coverd by sod would be x×(x+7)/2 sqft
(x+8)(x+8)=(x+7)^2+x^2
x'2+16x+64=x'2+14x+49+x^2
x^2-2x=15
x×(x-2)=15
x=5
(15+8)×$4.23=$97.29 for fencing
32.5sqft×$12.72=$413.4 for the sod
