Solve the inequality , find the max possible value for the variable.
3t + 1 < t + 12
2t < 11
t < 5.5
t_max = 5.5
For the second question just solve as two separate inequalities
4 +2 < x <= 7 + 2
6 <x <= 9
x in ]6, 9]
Answer:
10 - 6x
Step-by-step explanation:
Distribute the values inside parentheses.
2(-3x + 5)
(2 * -3x) + (2 * 5)
Simplify.
-6x + 10
Rearrange.
10 - 6x
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Step-by-step explanation:
Answer:
7/8
Step-by-step explanation:
you find the common denominator which is 2 so you can divide both by two to get 7/8