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Monica [59]
3 years ago
10

The pre image STU has undergone a type of transformation called a rigid transformation to produce the imagine VWX . Compare the

measures of the triangles by dragging the imagine to the pre image . Which measures are equal ? Check all that apply .

Mathematics
2 answers:
pshichka [43]3 years ago
8 0
I think they all apply (tick all the statements) since a rigid transformation doesn’t affect the shape of the triangle simply it’s position.
Genrish500 [490]3 years ago
3 0

Answer:

trick answe it is all of them on edgenunity 2020

Step-by-step explanation:

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Pani-rosa [81]

The rate of the slower jet is 672 miles per hour.

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<h3>How to find the rate of the jets?</h3>

Two jets leave an air base at the same time and travel in opposite directions.

One jet travels 80 mi/h faster than the other.

let

x = rate of the slower jet

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Therefore,

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The two jets are 11392 miles apart.

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divide both sides by 16

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learn  more on rate here: brainly.com/question/13975895

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3 0
2 years ago
Find sin 105 degrees by using 105 degrees = 60 degrees + 45 degrees
finlep [7]
This is the rule of sums of trig identities.  It says that sin(a + b) = sina*cosb+sinb*cosa.  Set up your right triangles.  In a 30-60-90 triangle, the side across from the 60 angle is the square root of 3, the side across from the 30 is 1, and the hypotenuse is 2.  In a 45-45-90 the sides across from the 45 degree angles are 1 and the hypotenuse is square root of 2.  With that being said, the sin of 60 is \frac{ \sqrt{3} }{2} and the cos of 60 is 1/2.  Both the sin and cos of 45 is \frac{1}{ \sqrt{2} }.  So your formula is filled in like this: ( \frac{ \sqrt{3} }{2} * \frac{1}{ \sqrt{2} })+( \frac{1}{2} * \frac{1}{ \sqrt{2} }).  When you do the multiplication on those sets of parenthesis, you get \frac{ \sqrt{3} }{2 \sqrt{2} } + \frac{1}{2 \sqrt{2} }.  When you add those your solution is \frac{1+ \sqrt{3} }{2 \sqrt{2} }.  Depending upon your instructor you may have to rationalize that denominator to get that radical out from under there, but if not, that's pretty much it!
8 0
3 years ago
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densk [106]

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