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Cloud [144]
3 years ago
15

Plzz help i will give brainliest plzzzz

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
8 0
B is the answer
At least that’s what my teacher said.
Rashid [163]3 years ago
6 0

Answer:

B

Step-by-step explanation:

B gives you 8/12, which can be simplified down to 2/3.

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What is 64% of 680kg
Anuta_ua [19.1K]

Answer:

435.2kg (1DP)

Step-by-step explanation:

0.64x680

64 divided by 100 = 0.64

4 0
3 years ago
Read 2 more answers
Ethan spends 4 dimes on a plastic crab and then Sophia buys a pink flamingo pen for 1 quarter how much money do they spend in al
slega [8]

Answer:

10+10+10+10+25= 65 cents

5 0
2 years ago
What is the missing numerator of 4/9= ?/81
yKpoI14uk [10]
To solve this question, first cross multiply
Let ? = x

4/9 = x/81

4(81) = 9(x)

Simplify.

81 x 4 = 324

324 = 9x

Isolate the x, divide 9 from both sides

324/9 = 9x/9

x = 324/9

x = 36


4/9 = 36/81

36 is your answer

hope this helps!
4 0
3 years ago
Read 2 more answers
Someone please help me. I’d really appreciate all your help❤️
kifflom [539]

Answer:

Step-by-step explanation:

1

A. negative

B. symmetric

C. positive

2

A. less than

B. same

C. greater than  

3 0
3 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
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